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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex2_10.sce.
+
+clc;
+clear;
+R1=4;
+R2=3;
+R3=5;
+R4=6;
+
+//CASE (a)
+Vs1=80;
+VA1=(Vs1/R3)/((1/R1)+(1/R2)+(1/R3)+(1/R4)); 
+I1dash=VA1/R1;               //From ohm's law(V=IR)
+I2dash=VA1/R2;
+I3dash=(Vs1-VA1)/R3;
+I4dash=VA1/R4;
+
+//CASE (b)
+Vs2=90;
+VA2=(Vs2/R2)/((1/R1)+(1/R2)+(1/R3)+(1/R4));
+I1doubledash=VA2/R1;
+I2doubledash=(Vs2-VA2)/R2;
+I3doubledash=VA2/R3;
+I4doubledash=VA2/R4;
+
+//CASE (c)
+Is=20;
+VA3=Is/((1/R1)+(1/R2)+(1/R3)+(1/R4));
+I1tripledash=VA3/R1;
+I2tripledash=VA3/R2;
+I3tripledash=VA3/R3;
+I4tripledash=VA3/R4;
+I1=I1dash+I1doubledash+I1tripledash;
+I2=-I2dash+I2doubledash-I2tripledash;
+I3=I3dash-I3doubledash-I3tripledash;
+I4=I4dash+I4doubledash+I4tripledash;
+printf("\n  Current in 4 ohm resitance=%2.1f A \n",I1)
+printf("\n  Current in 3 ohm resitance=%1.2f A \n",I2)
+printf("\n  Current in 5 ohm resitance=%d A \n",I3)
+printf("\n  Current in 6 ohm resitance=%2.1f A \n",I4)
+
+//The answer vary dueto roundoff error