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+// exa 9.4 Pg 260
+clc;clear;close;
+
+// Given Data
+W=25;// kN
+two_beta=29;// degree
+v=0.96;// m/min
+mu=0.14;// coefficient of thread friction
+Di=30;// mm
+Do=66;// mm
+mu_c=0.15;// coefficient of collar friction
+d=36;// mm
+p=6;// mm
+Sut=630;// MPa
+Syt=380;// MPa
+
+dm=d-p/2;// mm
+dc=d-p;// mm
+l=2*p;// mm
+alfa=atand(l/(%pi*dm));// degree
+mu_e=mu/cosd(two_beta/2);// virtual coefficient of friction
+fi=atand(mu_e);// degree
+Tf=W*10**3*dm/2*tand(alfa+fi);// N.mm
+Tc=mu_c*W*10**3/4*(Do+Di);// N.mm
+T=Tf+Tc;// N.mm
+N=v*10**3/l;// rpm
+
+P=2*%pi*N*T/(60*10**3)*10**-3;// kW
+printf('\n Power required to drive the slide = %.2f kN',P)
+sigma_c=4*W*10**3/(%pi*dc**2);// MPa
+tau=16*T/(%pi*dc**3);// MPa
+sigma1=1/2*(sigma_c+sqrt(sigma_c**2+4*tau**2));// MPa
+tau_max=sqrt((sigma_c/2)**2+tau**2);// MPa
+n_t=Syt/sigma1;// factor of safety in tension
+printf('\n factor of safety in tension = %.2f ',n_t)
+n_s=Syt/2/tau_max;// factor of safety in shear
+printf('\n factor of safety in shear = %.2f ',n_s)
+// Note- Answer in the textbook are not accurate.