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+// Problem 5.1,Page no.121
+
+clc;clear;
+close;
+
+b=100 //mm //width of timber joist
+d=200 //mm //depth of joist
+L=3 //m //Length of beam
+sigma=7 //KN/mm**2 //bending stress
+w_1=5 //KN/mm**2 //unit weight of timber
+
+//Calculations
+w=0.1*0.2*1*5*100 //N/m //self weight of the joist
+I_xx=1*12**-1*100*200**3 //mm**4 //M.I of section about N.A
+
+//M=W*L+w*L**2*2**-1 //Max Bending moment
+//Therefore,M=(3*W+450)
+
+//using the relation M*I**-1=sigma*y**-1,we get
+W=(((7*2*10**8)*(100*10**3*3)**-1)-450)*3**-1 //N //Max Load applied
+
+//Result
+printf("The Max value of Load applied is %.2f N",W)