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+// Problem no 4.4.12,Page No.102
+
+clc;clear;
+close;
+F_C=5 //KN //Pt Load at C
+F_D=4 //KN //Pt Load at D
+L_BC=1.25 //m //Length of BC
+L_DB=1 //m //Length of DB
+L_AD=3 //m //Length of AD
+w=2 //KN/m //u.d.l
+L=5.25 //m //Length of beam
+
+//Calculations
+
+//Let R_A & R_B be the reactions at A & B
+//R_A+R_B=15
+
+//Taking Moment at A
+//M_A=0=F_C*L-R_B*(L_DB+L_AD)+F_D*L_AD+w*L_AD**2*2**-1
+R_B=-(-F_C*L-F_D*L_AD-w*L_AD**2*2**-1)*(L_DB+L_AD)**-1
+R_A=15-R_B
+
+//Shear Force Calculations
+
+//Shear Force at C
+V_C=-F_C
+
+//Shear Force at B
+V_B1=V_C
+V_B2=V_C+R_B
+
+//Shear Force at D
+V_D1=V_B2
+V_D2=V_B2-F_D
+
+//Shear Force at A
+V_A=-(w*L_AD)-F_D-F_C+R_B
+
+//Pt of contraflexure
+//Let E be the pt and BE=x
+//V_E=0=-F_C+R_B-F_D-w*(L_BE-L_DB)
+L_BE=-((F_C-R_B+F_D)*w**-1-L_DB);
+x=L_BE;
+//Bending Moment Calculations
+
+//Bending Moment at C
+M_C=0
+
+//Bending Moment at B
+M_B=-F_C*L_BC
+
+//Bending Moment at D
+M_D=-F_C*(L_DB+L_BC)-R_B*L_DB
+
+//Bending Moment at A
+M_A=-F_C*L+R_B*(L_DB+L_AD)-F_D*L_AD-w*L_AD**2*2**-1
+
+//Bending Moment at E
+L_ED=L_BE-L_DB
+M_E=-F_C*(L_BC+L_BE)+R_B*L_BE-F_D*(L_BE-L_DB)-w*(L_BE-L_DB)**2*2**-1
+
+//Result
+printf("The Shear Force and Bending Moment Diagrams are the results")
+
+//Plotting the Shear Force Diagram
+subplot(2,1,1)
+X1=[0,L_BC,L_BC,L_BC+L_DB,L_BC+L_DB,L_BC+L_DB+L_AD,L_BC+L_DB+L_AD]                   
+Y1=[V_C,V_B1,V_B2,V_D1,V_D2,V_A,0]
+Z1=[0,0,0,0,0,0,0]
+plot(X1,Y1,X1,Z1)
+xlabel("Length x in m")
+ylabel("Shear Force in kN")
+title("the Shear Force Diagram")
+
+//Plotting the Bending Moment Diagram
+subplot(2,1,2)
+X2=[0,L_BC,L_BC+L_DB,L_BC+L_DB+L_ED,L_BC+L_DB+L_AD]
+Y2=[M_C,M_B,M_D,M_E,M_A]          
+Z2=[0,0,0,0,0]
+plot(X2,Y2,X2,Z2)
+xlabel("Length in m")
+ylabel("Bending Moment in kN.m")
+title("the Bending Moment Diagram")