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+clc;
+Pm=100000;
+V=420;
+P=6;
+f=50;
+sfl=0.04;
+smT=0.2;
+
+//for part a
+disp('for part a');
+Pg=Pm/(1-sfl);
+Ws=(4*%pi*f)/P;
+Tefl=Pg/Ws;
+//a=Tefl/Tem
+a=(1/(2/((sfl/smT)+(smT/sfl))));
+Tem=a*Tefl;
+mprintf('Maximum Torque is %f Nm \n',Tem);
+
+//for part b
+disp('for part b');
+//b=Test/Tem
+b=2/((1/smT)+(smT));
+Test=b*Tem;
+mprintf('The starting Torque is %f Nm \n',Test)
+
+//for part c
+disp('for part c');
+Prot=sfl*Pg;
+mprintf('Rotor Ohmic losses are %f W \n',Prot)
+
+//for part d
+disp('for part d');
+//Output is proportional to (s(1-s))/r2
+//Given conditions gives the equation as s1*s1-s1+0.0768
+Q=[1 -1 0.0768];
+R=roots(Q);
+s1=R(2);
+mprintf('Slip is %f \n',s1)
+
+//for part e
+disp('for part e');
+Tefl=(Pm/(1-s1))/Ws;
+mprintf('full-load torque is %f Nm \n',Tefl)
+
+//for part f
+disp('for part f');
+smT1=2*smT;
+mprintf('slip at maximum torque is %f',smT1);
+
+
+
+
+
+
+
+