diff options
Diffstat (limited to '3760/CH4/EX4.19')
-rw-r--r-- | 3760/CH4/EX4.19/Ex4_19.sce | 45 |
1 files changed, 45 insertions, 0 deletions
diff --git a/3760/CH4/EX4.19/Ex4_19.sce b/3760/CH4/EX4.19/Ex4_19.sce new file mode 100644 index 000000000..e5e438788 --- /dev/null +++ b/3760/CH4/EX4.19/Ex4_19.sce @@ -0,0 +1,45 @@ +clc;
+n=1500; // speed of generator
+// data is given in question for magnetising curve at n=1500 rpm
+If=[ 0 0.4 0.8 1.2 1.6 2 2.4 2.8 3];
+Ea=[6 60 120 172.5 202.5 221 231 237 240];
+subplot(221);
+plot(If,Ea);
+xlabel('field current');
+ylabel('generated EMF');
+title('Magnetising curve for n=1500');
+disp('case a')
+rf=100; // field resistance
+// rf=100 lets say voltage=240 and field current=2.4 which is shown by point A, straight line passing through A and origin meets magnetising current at B which is no load voltage
+Eo=230;
+printf('No load voltage is %f V\n',Eo);
+disp('case b');
+// a line OF is drawn passing through origin slope of this line gives critical resistance
+vt=180; // terminal voltage
+ifl=1.2; // field current corresponding to terminal voltage
+rfl=vt/ifl;
+printf('Critical value of shunt field resistance is %f ohms\n',rfl);
+disp('case c');
+// Choose S (any point) on linear part of magnetising curve.A vertical line from S meets field resistance line at t and horizontal line at y. Now
+e1=90; // terminal voltage corresponding to point s
+e2=60; // terminal voltage corresponding to point t
+n2=(e2/e1)*n;
+printf('Critical speed for given shunt field resistance is %f rpm\n',n2);
+disp('case d');
+n3=1200; // speed at which magnetising curve is drawn
+// data for magnetising curve at n=1200 can be obtained by multiplying voltage of magnetising curve at n=1500 by factor 1200/1500 and at point C field resistance line for 100 ohms meet at magnetising curve .This point gives no load EMF
+EAn=Ea*(n3/n);
+subplot(222);
+plot(If,EAn);
+xlabel('field current');
+ylabel('generated EMF');
+title('Magnetising curve for n=1200');
+Eo=165;
+printf('No load EMF is %f V\n',Eo);
+disp('case e');
+ia=50; // armature current
+ra=0.3; // armature resistance
+vd=ia*ra; // armature resistance drop
+// To obtain terminal voltage cut OD equal to vd and draw DG parallel to field resistance line. From G draw vertical line meeting field resistance line at H. Point corresponding to H gives terminal voltage which is
+vt=207;
+printf('Terminal voltage is %f V\n',vt);
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