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Diffstat (limited to '3733/CH24/EX24.24')
-rw-r--r-- | 3733/CH24/EX24.24/Ex24_24.sce | 30 |
1 files changed, 30 insertions, 0 deletions
diff --git a/3733/CH24/EX24.24/Ex24_24.sce b/3733/CH24/EX24.24/Ex24_24.sce new file mode 100644 index 000000000..80988f573 --- /dev/null +++ b/3733/CH24/EX24.24/Ex24_24.sce @@ -0,0 +1,30 @@ +// Example 24_24
+clc;funcprot(0);
+//Given data
+T_1=300;// K
+p_1=1;// bar
+T_4=870+273;// K
+p_r=6;// Pressure ratio
+e=0.65;// The effectiveness of heat exchanger
+n_c=0.8;// Isentropic efficiency of compressor
+n_t=0.85;// Isentropic efficiency of turbine
+n_g=0.95// Generator efficiency
+m_a=5;// kg/sec
+C_p=1;// kJ/kg.K
+r=1.4;// Specific heat ratio
+
+//Calculation
+//(a)
+T_2a=T_1*(p_r)^((r-1)/r);// K
+T_2=((T_2a-T_1)/n_c)+T_1;// K
+T_5a=T_4/(p_r)^((r-1)/r);// K
+T_5=T_4-(n_t*(T_4-T_5a));// K
+W_n=m_a*C_p*((T_4-T_5)-(T_2-T_1))*n_g;// kW
+//(b)
+T_3=T_2+(e*(T_5-T_2));// K
+n_th=((C_p*((T_4-T_5)-(T_2-T_1)))/(C_p*(T_4-T_3)))*100;// Thermal efficiency of the plant in %
+T_6=T_5-(T_3-T_2);// K
+//(c)
+Q=(m_a*60)*C_p*(T_6-T_1);// KJ/min
+printf('\n(a)Power output of the plant=%0.2f kW \n(b)Thermal efficiency of the plant=%0.1f percentage \n(c)Heat carried by the exhaust gases=%0.0f kJ/min',W_n,n_th,Q);
+// The answer vary due to round off error
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