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+//Chapter 3: Thermodynamic and Chemical Equilibrium
+//Problem: 12
+clc;
+
+//Declaration of Variables
+d_g_25 = - 85.77 // k J, Free Energy at 25 C
+d_g_35 = - 83.68 // k J, Free Energy at 35 C
+Ti = 273 + 25 // K
+Tf = 273 + 35 // K
+
+// Solution
+mprintf("Equating the entropy change at both the temperatures.\n")
+mprintf(" (d_h + d_g_25) / Ti = (d_h + d_g_35) / Tf\n")
+d_h = - 148
+mprintf(" The change in enthalpy for the process at 30C is %d kJ", d_h)