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+
+clear//
+
+//Variable Declaration
+Ga=4*10**6 //Bulk modulus of Aluminium in psi
+Gs=12*10**6 //Bulk Modulus of Steel in psi
+T=10**4 //Torque in lb.in
+L1=3 //Length in ft of the Steel bar
+L2=6 //Length in ft of the Aluminium bar
+d1=3 //Diameter of the Aluminium bar in inches
+d2=2 //Diameter of the Steel bar in inches
+
+//Calculations
+//Using Compatibility and equlibrium conditions
+a=([[1,1;(L1*32)/(Gs*%pi*d2**4),-((L2*32)/(Ga*d1**4*%pi))]])
+b=([T;0])
+y=linsolve(a,b)
+
+//Stresses
+t_max_st=(16*-y(1))/(%pi*d2**3) //Max shear Stress in Steel in psi
+t_max_al=(16*-y(2))/(%pi*d1**3) //Max shear stress in aluminium in psi
+
+printf("\n The maximum values of Shear Stresses are as follows")
+printf("\n %0.1f psi in Steel and %0.1f psi in aluminium",(t_max_st),t_max_al)