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diff --git a/3681/CH8/EX8.2/Ans8_2.PNG b/3681/CH8/EX8.2/Ans8_2.PNG
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diff --git a/3681/CH8/EX8.2/Ex8_2.sce b/3681/CH8/EX8.2/Ex8_2.sce
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+// Calculating the stress on the ring
+clc;
+disp('Example 8.2, Page No. = 8.8')
+// Given Data
+rpm = 3000;// Speed in r.p.m.
+Rm = 0.35;// Radius of overhang (in meter)
+Rmr = 0.49;// Radius of ring (in meter)
+G = 300;// Weight of copper winding (in kg)
+gr = 7800;// Density of ring material (in kg per meter cube)
+tb = 350*45*10^(-6);// Area of retaining ring
+// Calculation of the stress on the ring
+n = rpm/60;// Speed in r.p.s
+Dm = 2*Rm;// Diameter of overhang (in meter)
+Dmr = 2*Rmr;// Diameter of ring (in meter)
+ft = (%pi*n*n*G*Dm/tb)+(%pi*%pi*n*n*gr*Dmr*Dmr);// Stress on ring (in Newton per meter square)
+disp(ft,'Stress on ring (Newton per meter square)=');
+//in book answer is 289.5 (MN per meter square).  The answers vary due to round off error
diff --git a/3681/CH8/EX8.4/Ans8_4.PNG b/3681/CH8/EX8.4/Ans8_4.PNG
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+++ b/3681/CH8/EX8.4/Ans8_4.PNG
diff --git a/3681/CH8/EX8.4/Ex8_4.sce b/3681/CH8/EX8.4/Ex8_4.sce
new file mode 100644
index 000000000..8ae86eb05
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+// Calculating the tensile stress and factor of safety
+clc;
+disp('Example 8.4, Page No. = 8.12')
+// Given Data
+rpm = 3000;// Speed in r.p.m.
+Dr1 = 1.15;// Outer diameter  of rotor (in meter)
+Nrs = 39;// Number of rotor slot
+Drs = 140;// Depth of rotor slot (in mm)
+Wrs = 45;// Width of rotor slot (in mm)
+gs = 7800;// Density of steel (in kg per meter cube)
+yield_stress = 520*10^(6);// Yield stress of rotor steel (in Newton per meter square)
+// Calculation of the tensile stress and factor of safety
+n = rpm/60;// Speed in r.p.s
+Dr2 = Dr1-2*Drs*10^(-3);// Diameter of rotor at the bottom of slots (in meter)
+t = (%pi*Dr2*10^(3)/Nrs)-Wrs;// Width of tooth at the bottom of slot (in mm)
+alpha = 360/Nrs;// Angle subtended by each slot (in degree)
+f = %pi^(3)/(3*t*10^(-3))*gs*n*n*(alpha/360)*(Dr1^(3)-Dr2^(3));// Tensile stress (in Newton per meter square)
+disp(f,'Tensile stress at the root of the teeth at normal operating speed (Newton per meter square)=');
+f_20 = 1.2^(2)*f;// Tensile stress at 20% over speed.  Since centrifugal force is propartional of square of speed
+disp(yield_stress/f_20,'Factor of safety at 20% over speed =');
+//in book answers are 178 (Mega Newton per meter square) and 2.03 respectively.  The answers vary due to round off error
diff --git a/3681/CH8/EX8.5/Ans8_5.PNG b/3681/CH8/EX8.5/Ans8_5.PNG
new file mode 100644
index 000000000..ee475d521
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+++ b/3681/CH8/EX8.5/Ans8_5.PNG
diff --git a/3681/CH8/EX8.5/Ex8_5.sce b/3681/CH8/EX8.5/Ex8_5.sce
new file mode 100644
index 000000000..6225abdb8
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+++ b/3681/CH8/EX8.5/Ex8_5.sce
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+// Calculating the inertia constant of the generator
+clc;
+disp('Example 8.5, Page No. = 8.14')
+// Given Data
+P = 500;// Power rating (in MW)
+f = 50;// Frequency (in Hz)
+J = 50*10^(3);// Moment of inertia (in kg-meter square)
+pf = 0.85;// Power factor
+// Calculation of the inertia constant of the generator
+w = 2*%pi*f;// Angular speed (in rad/s)
+Q = 500*10^(3)/pf;// kVA rating
+H = (1/2)*J*w*w/(Q*10^(3));// Inertia constant (in seconds)
+disp(H,'Inertia constant (seconds)=');
+//in book answer is 4.2 seconds.  The answers vary due to round off error