diff options
Diffstat (limited to '3535/CH1')
-rw-r--r-- | 3535/CH1/EX1.1/Ex1_1.sce | 13 | ||||
-rw-r--r-- | 3535/CH1/EX1.2/Ex1_2.sce | 11 | ||||
-rw-r--r-- | 3535/CH1/EX1.3/Ex1_3.sce | 15 | ||||
-rw-r--r-- | 3535/CH1/EX1.4/Ex1_4.sce | 12 |
4 files changed, 51 insertions, 0 deletions
diff --git a/3535/CH1/EX1.1/Ex1_1.sce b/3535/CH1/EX1.1/Ex1_1.sce new file mode 100644 index 000000000..d69999d39 --- /dev/null +++ b/3535/CH1/EX1.1/Ex1_1.sce @@ -0,0 +1,13 @@ +//Chapter 1, Example 1.1, Page 21 +clc +clear +//Find Atomic weight of Boron +I10 = 0.199 // Isotopic abundance of B10 (Value used in question is wrong) +A10 = 10.012937 //Atomic weight of B10 +I11 = 0.801 // Isotopic abundance of B11 +A11 = 11.009306 //Atomic weight of B11 +//Calculation +W = (I10*A10)+(I11*A11) +printf("The atomic weight of Boron = %f",W); + +//Answers may vary due to round off error diff --git a/3535/CH1/EX1.2/Ex1_2.sce b/3535/CH1/EX1.2/Ex1_2.sce new file mode 100644 index 000000000..b7951ee79 --- /dev/null +++ b/3535/CH1/EX1.2/Ex1_2.sce @@ -0,0 +1,11 @@ +//Chapter 1, Example 1.2, Page 22 +clc +clear +//Find number of 10B molecules in 5g of Boron +m = 5 //g +Na = 0.6022*10**24 //atoms/mol +AB = 10.811 //Atomic weight of 10B , g/mol +NB = (m*Na)/(AB) +printf("The number of Boron atoms = %e atoms",NB); + +//Answers may vary due to round off error diff --git a/3535/CH1/EX1.3/Ex1_3.sce b/3535/CH1/EX1.3/Ex1_3.sce new file mode 100644 index 000000000..dbf7ebbcb --- /dev/null +++ b/3535/CH1/EX1.3/Ex1_3.sce @@ -0,0 +1,15 @@ +//Chapter 1, Example 1.3, Page 22 +clc +clear +//Estimate the mass on an atom of U 238. From Eq. (1.3) +//Calculating the approximate weight +Mapprox = 238/(6.022*10**23) +//Calculating the precise weight +M = 238.050782/(6.022142*10**23) +printf("The approximate mass on an atom of U 238 = %e g/atom",Mapprox); +printf("\n The precise mass on an atom of U 238 = %e g/atom",M); +printf("Varies by a negligible error") +//Answers may vary due to round off error + + + diff --git a/3535/CH1/EX1.4/Ex1_4.sce b/3535/CH1/EX1.4/Ex1_4.sce new file mode 100644 index 000000000..7ca5889cc --- /dev/null +++ b/3535/CH1/EX1.4/Ex1_4.sce @@ -0,0 +1,12 @@ +//Chapter 1, Example 1.4, Page 23 +clc +clear +//Density of Hydrogen atom in water +p = 1 // density of water in g cm^-3 +Na = 6.022*10^23 // molucules/mol +A = 18 // atomic weight of water in g/mol +N = (p*Na)/A +NH = 2*N +printf("The density of water = %e molecules/cm3",N); +printf("\n The density of hydrogen atoms = %e atoms/cm3",NH); +//Answers may vary due to round off error |