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+//Example 2// Ch 5
+clc;
+clear;
+close;
+// given data
+d = 0.001;//in meters
+p = 101.3; //gas pressure in kPa
+C = -2400.4;//constant value
+A = 0.027;//constant value
+As = 10^8;//avalanche size
+//secondary ionization coefficient is much smaller than unity therefore ionization coefficient (alpha) is equal to electron attachment coefficient 
+E = (2400.4*p)/0.027; //alpha is equal to e- attachment coeff occurs at this eq
+Vs1 = E*d;//breakdown voltage in V
+printf("electric field %e V/m \n",E)
+printf("breakdown voltage %f V \n",Vs1)
+Vs2 = (log(As)-C*p*d)/A; //in V
+printf("breakdown voltage corresponding to an avalanche size %f V \n",Vs2)
+//as the avalanche self-space charge is neglected the breakdown voltage will be same irrespective of the polarity of the stressed plate acc. to eq (5.4) N2>=N1;
+Vspos = 9.4;//in kV when N2>=N1 in which no of e- in second avalanche is greater than equal to no of e- in first avalanche
+printf("positive voltage breakdown %f kV \n",Vspos)
+Vsneg = 9.2;//in kV when Neph >= 1 where Neph is no of e-photoemitted from the cathode
+printf("negative voltage breakdown %f kV \n",Vsneg)