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diff --git a/3472/CH43/EX43.3/Example43_3.sce b/3472/CH43/EX43.3/Example43_3.sce new file mode 100644 index 000000000..b34a37915 --- /dev/null +++ b/3472/CH43/EX43.3/Example43_3.sce @@ -0,0 +1,29 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART IV : UTILIZATION AND TRACTION
+// CHAPTER 5: ELECTRIC TRACTION-SPEED TIME CURVES AND MECHANICS OF TRAIN MOVEMENT
+
+// EXAMPLE : 5.3 :
+// Page number 778-779
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+speed = 25.0 // Scheduled speed(kmph)
+D = 800.0/1000 // Distance between 2 stations(km)
+t = 20.0 // Time of stop(sec)
+V_m_per = 20.0 // Maximum speed higher than(%)
+beta = 3.0 // Retardation(km phps)
+
+// Calculations
+t_total = D*3600/speed // Total time of run including stop(sec)
+T = t_total-t // Actual time for run(sec)
+V_a = D/T*3600 // Average speed(kmph)
+V_m = (100+V_m_per)*V_a/100 // Maximum speed(kmph)
+alpha = 1/((7200.0*D/V_m**2*((V_m/V_a)-1))-(1/beta)) // Value of acceleration(km phps)
+
+// Results
+disp("PART IV - EXAMPLE : 5.3 : SOLUTION :-")
+printf("\nRate of acceleration required to operate this service, α = %.2f km phps", alpha)
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