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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 6 Example 10")
+p1=800;//initial pressure of steam in Kpa
+T1=200;//initial temperature of steam in degree celcius
+disp("here steam is kept in rigid vessel,therefore its specific volume shall remain constant")
+disp("it is superheated steam as Tsat=170.43 degree celcius at 800 Kpa")
+disp("from superheated steam table;v1=0.2404 m^3/kg")
+disp("at begining of condensation specific volume = 0.2404 m^3/kg")
+disp("v2=0.2404 m^3/kg")
+v2=0.2404;
+disp("this v2 shall be specific volume corresponding to saturated vapour state for condensation.")
+disp("thus v2=vg=0.2404 m^3/kg")
+vg=v2;
+disp("looking into steam table vg=0.2404 m^3/kg shall lie between temperature 175 degree celcius(vg=0.2168 m^3/kg)and 170 degree celcius(vg=0.2428 m^3/kg)and pressure 892 Kpa(175 degree celcius)and 791.7 Kpa(170 degree celcius).")
+disp("by interpolation,temperature at begining of condensation(T2)in K")
+T2=175-((175-170)*(0.2404-0.2167))/(0.2428-.2168)
+disp("similarily,pressure(p2)in Kpa")
+p=892-(((892-791.7)*(0.2404-0.2168))/(0.2428-0.2168))