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+//find value of P
+clc
+//solution
+//given
+//refer fig 9.29 and 9.30
+T=100//N/mm^2
+n=4
+d=20//mm
+//Ps=P/4=0.25*P//N
+e=100//mm
+//T1=P*e//turning moment
+//la=ld=200=100//mm
+//lb=lc=100//mm
+//eqauting the moments equal to each other
+//P*e=(Fa/la)*[la^2+lb^2+lc^2+ld^2]
+//P*e=(Fa/la)*[2*300^2+2*100^2]
+//Fa=P*100*3/2000//N
+//Fa=0.15*P//N
+//Fb=Fa*lb/la=0.05*P//N
+//Fc=Fa*lc/la=0.05*P//N
+//Fd=Fa*ld/la=0.15*P//N
+//Ra=Ps-Fa=0.1*P
+//Rb=Ps-Fb=0.20*P
+//Rc=Ps+Fc=0.30*p
+//Rd=Ps+Fd=0.40*P//N
+//max load is Rd
+//therfore
+pi=3.14
+//Rd=(pi/4)*T*d^2
+//0.40*P=(pi/4)*T*d^2
+P=(pi/4)*T*d^2/0.40
+printf("the value of force P is,%f N",P) \ No newline at end of file