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-rwxr-xr-x278/CH22/EX22.13/ex_22_13.sce98
1 files changed, 49 insertions, 49 deletions
diff --git a/278/CH22/EX22.13/ex_22_13.sce b/278/CH22/EX22.13/ex_22_13.sce
index 39f90f169..72f86c8fe 100755
--- a/278/CH22/EX22.13/ex_22_13.sce
+++ b/278/CH22/EX22.13/ex_22_13.sce
@@ -1,50 +1,50 @@
-//find...
-clc
-//solution
-//given
-Do=1.8//m
-Di=1.35//m
-b=0.3//m
-N=250//rpm
-T=15000//N-m
-ftb=35//n/mm^2
-ftl=40//n/mm^2
-//w=1.25*h
-n=6
-fta=15//N/mm^2
-d1=150//mm
-rho=7200//kg/m^3
-D=(Do+Di)/2//m
-t=(Do-Di)/2//m
-v=(%pi*D*N)/60//m/s
-ft=rho*v^2*10^6//N/mm^2
-A=b*t//m^2
-Ft=ft*A*10^6//N
-//let dc be core dia
-//Ft=(%pi/4)*dc^2*ftb*4=110*dc^2
-//dc=sqrt(Ft/110)//mm
-printf("the core dia is,%f mm\n",sqrt(Ft/110))
-printf("the standard core dia is 48.65mm\n")
-dc=48.65//mm
-//let h be depth of link and w be width of link
-//w=1.25*h
-//Al=w*h=1.25*h^2
-//let Fmax be max tensile force
-Fmax=2*ft*A//N....eq1
-//Fmax=4*ftl*Al=200*h^2...eq2
-//from eq 1 and eq2
-h=46//mm
-w=1.25*h//mm
-printf("the heigth and width of of link is,%f mm\n,%f mm\n",h,w)
-//let a1 be major and b1 be minor axis
-//a1=2*b1
-n=6
-d=2*d1//m
-M=T*(D*1000-d)/(D*n*1000)//N-mm
-printf("bending moment is,%f N-mm\n",M*1000)
-//Z=(%pi/32)*b1*a1^2=0.05*a1^3
-//fb=M/Z
-a1=(M*1000/(fta*0.05))^(1/3)//mm
-b1=0.5*a1
-tf=40
+
+clc
+//solution
+//given
+Do=1.8//m
+Di=1.35//m
+b=0.3//m
+N=250//rpm
+T=15000//N-m
+ftb=35//n/mm^2
+ftl=40//n/mm^2
+//w=1.25*h
+n=6
+fta=15//N/mm^2
+d1=150//mm
+rho=7200//kg/m^3
+D=(Do+Di)/2//m
+t=(Do-Di)/2//m
+v=(%pi*D*N)/60//m/s
+ft=rho*v^2*10^6//N/mm^2
+A=b*t//m^2
+Ft=ft*A*10^6//N
+//let dc be core dia
+//Ft=(%pi/4)*dc^2*ftb*4=110*dc^2
+//dc=sqrt(Ft/110)//mm
+printf("the core dia is,%f mm\n",sqrt(Ft/110))
+printf("the standard core dia is 48.65mm\n")
+dc=48.65//mm
+//let h be depth of link and w be width of link
+//w=1.25*h
+//Al=w*h=1.25*h^2
+//let Fmax be max tensile force
+Fmax=2*ft*A//N....eq1
+//Fmax=4*ftl*Al=200*h^2...eq2
+//from eq 1 and eq2
+h=46//mm
+w=1.25*h//mm
+printf("the heigth and width of of link is,%f mm\n,%f mm\n",h,w)
+//let a1 be major and b1 be minor axis
+//a1=2*b1
+n=6
+d=2*d1//m
+M=T*(D*1000-d)/(D*n*1000)//N-mm
+printf("bending moment is,%f N-mm\n",M*1000)
+//Z=(%pi/32)*b1*a1^2=0.05*a1^3
+//fb=M/Z
+a1=(M*1000/(fta*0.05))^(1/3)//mm
+b1=0.5*a1
+tf=40
printf("major and minor axis is,%f mm\n,%f mm\n",a1,b1) \ No newline at end of file