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+//chapter23
+//example23.4
+//page514
+
+v=100 // V
+Vm=200 // V
+R_L=100 // ohm
+
+// since v=Vm*sin(theta), we get
+
+theta=asin(v/Vm)*180/%pi // in terms of degrees
+
+phi=180-theta
+
+V_avg=Vm*(1+cos(theta*%pi/180))/(2*%pi)
+
+I_avg=V_avg/R_L
+
+printf("firing angle = %.2f degrees \n",theta)
+printf("conduction angle = %.2f degrees \n",phi)
+printf("average current = %.4f A \n",I_avg)
+
+// the accurate answer for average current is 0.594 A but in book it is given as 0.5925 A