diff options
Diffstat (limited to '2459/CH19')
30 files changed, 211 insertions, 0 deletions
diff --git a/2459/CH19/EX19.1/Ex19_1.PNG b/2459/CH19/EX19.1/Ex19_1.PNG Binary files differnew file mode 100644 index 000000000..3295a46d4 --- /dev/null +++ b/2459/CH19/EX19.1/Ex19_1.PNG diff --git a/2459/CH19/EX19.1/Ex19_1.sce b/2459/CH19/EX19.1/Ex19_1.sce new file mode 100644 index 000000000..592a83af6 --- /dev/null +++ b/2459/CH19/EX19.1/Ex19_1.sce @@ -0,0 +1,11 @@ +//chapter19
+//example19.1
+//page416
+
+// the figure in book is for reference only as equations for Ec and Es are already explained in the theory in the book.
+
+printf("Ec=(Vmax+Vmin)/2 \n")
+printf("Es=(Vmax-Vmin)/2 \n")
+printf("But, Es=m*Ec \n")
+printf("So (Vmax-Vmin)/2 = m*(Vmax+Vmin)/2 \n")
+printf("thus, m = (Vmax-Vmin)/(Vmax+Vmin) \n")
diff --git a/2459/CH19/EX19.10/Ex19_10.PNG b/2459/CH19/EX19.10/Ex19_10.PNG Binary files differnew file mode 100644 index 000000000..1ee97f388 --- /dev/null +++ b/2459/CH19/EX19.10/Ex19_10.PNG diff --git a/2459/CH19/EX19.10/Ex19_10.sce b/2459/CH19/EX19.10/Ex19_10.sce new file mode 100644 index 000000000..6988255cc --- /dev/null +++ b/2459/CH19/EX19.10/Ex19_10.sce @@ -0,0 +1,13 @@ +//chapter19
+//example19.10
+//page423
+
+fc=500 // kHz
+fs=1 // kHz
+
+lower_sideband=fc-fs
+upper_sideband=fc+fs
+BW=upper_sideband-lower_sideband
+
+printf("sideband frequencies = %.3f kHz and %.3f kHz \n",lower_sideband,upper_sideband)
+printf("bandwidth required = %.3f kHz \n",BW)
diff --git a/2459/CH19/EX19.11/Ex19_11.PNG b/2459/CH19/EX19.11/Ex19_11.PNG Binary files differnew file mode 100644 index 000000000..e99f0ebd6 --- /dev/null +++ b/2459/CH19/EX19.11/Ex19_11.PNG diff --git a/2459/CH19/EX19.11/Ex19_11.sce b/2459/CH19/EX19.11/Ex19_11.sce new file mode 100644 index 000000000..c26d64a3b --- /dev/null +++ b/2459/CH19/EX19.11/Ex19_11.sce @@ -0,0 +1,13 @@ +//chapter19
+//example19.11
+//page423
+
+m=0.4
+Ic=8 // A
+// Pt=Pc+Ps and Ps=0.5*m^2*Pc so Pt=Pc*(1+m^2/2)
+// so Pt/Pc=1+m^2/2 but P is proportional to I^2 so
+// (It/Ic)^2=1+m^2/2 and thus we get
+
+It=Ic*(1+m^2/2)^0.5
+
+printf("antenna current for m=0.4 is = %.3f A \n",It)
diff --git a/2459/CH19/EX19.12/Ex19_12.PNG b/2459/CH19/EX19.12/Ex19_12.PNG Binary files differnew file mode 100644 index 000000000..48132afae --- /dev/null +++ b/2459/CH19/EX19.12/Ex19_12.PNG diff --git a/2459/CH19/EX19.12/Ex19_12.sce b/2459/CH19/EX19.12/Ex19_12.sce new file mode 100644 index 000000000..7d1341b7a --- /dev/null +++ b/2459/CH19/EX19.12/Ex19_12.sce @@ -0,0 +1,11 @@ +//chapter19
+//example19.12
+//page424
+
+It=8.93 // A
+Ic=8 // A
+
+// we know that (It/Ic)^2=1+m^2/2 so making m as subject we get
+m=(2*((It/Ic)^2-1))^0.5
+
+printf("modulation factor = %.3f or %.3f percent \n",m,m*100)
diff --git a/2459/CH19/EX19.13/Ex19_13.PNG b/2459/CH19/EX19.13/Ex19_13.PNG Binary files differnew file mode 100644 index 000000000..427611987 --- /dev/null +++ b/2459/CH19/EX19.13/Ex19_13.PNG diff --git a/2459/CH19/EX19.13/Ex19_13.sce b/2459/CH19/EX19.13/Ex19_13.sce new file mode 100644 index 000000000..3fd4e697a --- /dev/null +++ b/2459/CH19/EX19.13/Ex19_13.sce @@ -0,0 +1,13 @@ +//chapter19
+//example19.13
+//page424
+
+Vt=110 // V
+Vc=100 // V
+
+// since Pt/Pc=1+m^2/2 and P is proportional to V^2 we get (Vt/Vc)^2=1+m^2/2
+// making m as subject we get
+
+m=(2*((Vt/Vc)^2-1))^0.5
+
+printf("modulation factor = %.3f or %.3f percent \n",m,m*100)
diff --git a/2459/CH19/EX19.14/Ex19_14.PNG b/2459/CH19/EX19.14/Ex19_14.PNG Binary files differnew file mode 100644 index 000000000..8c1e5d859 --- /dev/null +++ b/2459/CH19/EX19.14/Ex19_14.PNG diff --git a/2459/CH19/EX19.14/Ex19_14.sce b/2459/CH19/EX19.14/Ex19_14.sce new file mode 100644 index 000000000..be01ac88b --- /dev/null +++ b/2459/CH19/EX19.14/Ex19_14.sce @@ -0,0 +1,23 @@ +//chapter19
+//example19.14
+//page424
+
+Vc=5 // V
+V_lower=2.5 // V
+V_upper=2.5 // V
+R=2 // kilo ohm
+
+// figure given in book is just for understanding purpose.It is not a part of solution.
+// however, the figure has been made in xcos and screenshot has been attached for reference
+
+// since power=(rms voltage)^2/R we get
+
+Pc=(0.707*Vc)^2/R
+P_lower=(0.707*V_lower)^2/R
+P_upper=(0.707*V_upper)^2/R
+Pt=Pc+P_lower+P_upper
+
+printf("power delivered by carrier = %.3f mW \n",Pc)
+printf("power delivered by lower sideband = %.3f mW \n",P_lower)
+printf("power delivered by upper sideband = %.3f mW \n",P_upper)
+printf("total power delivered by AM wave = %.3f mW \n",Pt)
diff --git a/2459/CH19/EX19.14/Figure19_14.JPG b/2459/CH19/EX19.14/Figure19_14.JPG Binary files differnew file mode 100644 index 000000000..3db4dfc69 --- /dev/null +++ b/2459/CH19/EX19.14/Figure19_14.JPG diff --git a/2459/CH19/EX19.2/Ex19_2.PNG b/2459/CH19/EX19.2/Ex19_2.PNG Binary files differnew file mode 100644 index 000000000..9b7500c37 --- /dev/null +++ b/2459/CH19/EX19.2/Ex19_2.PNG diff --git a/2459/CH19/EX19.2/Ex19_2.sce b/2459/CH19/EX19.2/Ex19_2.sce new file mode 100644 index 000000000..17a5275ad --- /dev/null +++ b/2459/CH19/EX19.2/Ex19_2.sce @@ -0,0 +1,17 @@ +//chapter19
+//example19.2
+//page416
+
+// figure is given in book for understanding purpose only.It is not required for solving the example as maximum and minimum peak voltages are given in the problem statement itself.
+
+Vmax_pp=16 // mV
+Vmin_pp=4 // mV
+
+Vmax=Vmax_pp/2
+Vmin=Vmin_pp/2
+
+m=(Vmax-Vmin)/(Vmax+Vmin)
+
+printf("modulation factor = %.3f \n",m)
+
+
diff --git a/2459/CH19/EX19.3/Ex19_3.PNG b/2459/CH19/EX19.3/Ex19_3.PNG Binary files differnew file mode 100644 index 000000000..781e6a5e9 --- /dev/null +++ b/2459/CH19/EX19.3/Ex19_3.PNG diff --git a/2459/CH19/EX19.3/Ex19_3.sce b/2459/CH19/EX19.3/Ex19_3.sce new file mode 100644 index 000000000..e055486c8 --- /dev/null +++ b/2459/CH19/EX19.3/Ex19_3.sce @@ -0,0 +1,10 @@ +//chapter19
+//example19.3
+//page417
+
+Es=50 // V
+Ec=100 // V
+
+m=Es/Ec
+
+printf("modulation factor = %.3f \n",m)
diff --git a/2459/CH19/EX19.4/Ex19_4.PNG b/2459/CH19/EX19.4/Ex19_4.PNG Binary files differnew file mode 100644 index 000000000..95466423f --- /dev/null +++ b/2459/CH19/EX19.4/Ex19_4.PNG diff --git a/2459/CH19/EX19.4/Ex19_4.sce b/2459/CH19/EX19.4/Ex19_4.sce new file mode 100644 index 000000000..3502e0608 --- /dev/null +++ b/2459/CH19/EX19.4/Ex19_4.sce @@ -0,0 +1,19 @@ +//chapter19
+//example19.4
+//page419
+
+fc=2500 // kHz
+fs_min=0.05 // kHz
+fs_max=15 // kHz
+
+upper_sideband_min=fc+fs_min
+upper_sideband_max=fc+fs_max
+
+lower_sideband_min=fc-fs_min
+lower_sideband_max=fc-fs_max
+
+BW=upper_sideband_max-lower_sideband_max
+
+printf("lower sideband is from %.3f to %.3f kHz \n",lower_sideband_min,lower_sideband_max)
+printf("upper sideband is from %.3f to %.3f kHz \n",upper_sideband_min,upper_sideband_max)
+printf("Bandwidth for RF amplifier = %.3f kHz \n",BW)
diff --git a/2459/CH19/EX19.5/Ex19_5.PNG b/2459/CH19/EX19.5/Ex19_5.PNG Binary files differnew file mode 100644 index 000000000..923173cd4 --- /dev/null +++ b/2459/CH19/EX19.5/Ex19_5.PNG diff --git a/2459/CH19/EX19.5/Ex19_5.sce b/2459/CH19/EX19.5/Ex19_5.sce new file mode 100644 index 000000000..b743848ea --- /dev/null +++ b/2459/CH19/EX19.5/Ex19_5.sce @@ -0,0 +1,27 @@ +//chapter19
+//example19.5
+//page420
+
+// v=5*(1+0.6*cos(6280*t))*sin(211d4*t) V
+// compare with v=Ec*(1+m*cos(ws*t))*sin(wc*t) we get
+Ec=5 // V
+m=0.6
+fs=6280/(2*%pi) // Hz
+fc=211d4/(2*%pi) // Hz
+
+Vmin=Ec-m*Ec
+Vmax=Ec+m*Ec
+
+f1=(fc-fs)/1000 // in kHz
+f2=fc/1000 // in kHz
+f3=(fc+fs)/1000 // in kHz
+
+V1=m*Ec/2
+V2=Ec
+V3=m*Ec/2
+
+printf("minimum amplitude = %.3f V and maximum amplitude = %.3f V \n",Vmin,Vmax)
+printf("frequency components = %.1f kHz, %.1f Hz, %.1fkHz \n",f1,f2,f3)
+printf("amplitudes of components = %.3f V, %.3f V, %.3f V \n",V1,V2,V3)
+
+// in book there is error of 0.2 kHz in every frequency component. The accurate answers are 334.8,335.8,336.8 kHz
diff --git a/2459/CH19/EX19.6/Ex19_6.PNG b/2459/CH19/EX19.6/Ex19_6.PNG Binary files differnew file mode 100644 index 000000000..734e33bd3 --- /dev/null +++ b/2459/CH19/EX19.6/Ex19_6.PNG diff --git a/2459/CH19/EX19.6/Ex19_6.sce b/2459/CH19/EX19.6/Ex19_6.sce new file mode 100644 index 000000000..81b60bd43 --- /dev/null +++ b/2459/CH19/EX19.6/Ex19_6.sce @@ -0,0 +1,15 @@ +//chapter19
+//example19.6
+//page420
+
+fc=1000 // kHz
+fs=5 // kHz
+m=0.5
+Ec=100 // V
+
+lower_sideband=fc-fs
+upper_sideband=fc+fs
+amplitude=m*Ec/2
+
+printf("lower and upper sideband frequencies = %.3f kHz and %.3f kHz \n",lower_sideband,upper_sideband)
+printf("amplitude of each sideband term = %.3f V \n",amplitude)
diff --git a/2459/CH19/EX19.7/Ex19_7.PNG b/2459/CH19/EX19.7/Ex19_7.PNG Binary files differnew file mode 100644 index 000000000..5569b0f40 --- /dev/null +++ b/2459/CH19/EX19.7/Ex19_7.PNG diff --git a/2459/CH19/EX19.7/Ex19_7.sce b/2459/CH19/EX19.7/Ex19_7.sce new file mode 100644 index 000000000..ba286e153 --- /dev/null +++ b/2459/CH19/EX19.7/Ex19_7.sce @@ -0,0 +1,12 @@ +//chapter19
+//example19.7
+//page422
+
+Pc=500 // W
+m=1
+
+Ps=0.5*m^2*Pc
+Pt=Pc+Ps
+
+printf("sideband power = %.3f W \n",Ps)
+printf("power of modulated wave = %.3f W \n",Pt)
diff --git a/2459/CH19/EX19.8/Ex19_8.PNG b/2459/CH19/EX19.8/Ex19_8.PNG Binary files differnew file mode 100644 index 000000000..ed67c2e81 --- /dev/null +++ b/2459/CH19/EX19.8/Ex19_8.PNG diff --git a/2459/CH19/EX19.8/Ex19_8.sce b/2459/CH19/EX19.8/Ex19_8.sce new file mode 100644 index 000000000..3dc0d537e --- /dev/null +++ b/2459/CH19/EX19.8/Ex19_8.sce @@ -0,0 +1,13 @@ +//chapter19
+//example19.8
+//page422
+
+m1=0.8
+m2=0.1
+Pc=50 // kW
+
+Ps1=0.5*m1^2*Pc
+Ps2=0.5*m2^2*Pc
+
+printf("for m=0.8, sideband power = %.3f kW \n",Ps1)
+printf("for m=0.1, sideband power = %.3f kW \n",Ps2)
diff --git a/2459/CH19/EX19.9/Ex19_9.PNG b/2459/CH19/EX19.9/Ex19_9.PNG Binary files differnew file mode 100644 index 000000000..07b29adfc --- /dev/null +++ b/2459/CH19/EX19.9/Ex19_9.PNG diff --git a/2459/CH19/EX19.9/Ex19_9.sce b/2459/CH19/EX19.9/Ex19_9.sce new file mode 100644 index 000000000..2ec82705a --- /dev/null +++ b/2459/CH19/EX19.9/Ex19_9.sce @@ -0,0 +1,14 @@ +//chapter19
+//example19.9
+//page422
+
+// block diagram is for understanding purpose inly.It is not required to solve the example
+m=1
+eta=0.72
+// carrier is not affected by modulating signal so its power level remains unchanged before and after modulation
+Pc=40 // kW
+Ps=0.5*m^2*Pc
+P_audio=Ps/eta
+
+printf("carrier power after modulation = %.3f kW \n",Pc)
+printf("required audio power = %.3f kW \n",P_audio)
diff --git a/2459/CH19/EX19.9/Figure19_9.JPG b/2459/CH19/EX19.9/Figure19_9.JPG Binary files differnew file mode 100644 index 000000000..c60633d57 --- /dev/null +++ b/2459/CH19/EX19.9/Figure19_9.JPG |
