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-rwxr-xr-x24/CH26/EX26.1/Example26_1.sce11
-rwxr-xr-x24/CH26/EX26.1/Example26_1_result.txt2
-rwxr-xr-x24/CH26/EX26.2/Example26_2.sce20
-rwxr-xr-x24/CH26/EX26.2/Example26_2_result.txt5
-rwxr-xr-x24/CH26/EX26.3/Example26_3.sce11
-rwxr-xr-x24/CH26/EX26.3/Example26_3_result.txt2
-rwxr-xr-x24/CH26/EX26.4/Example26_4.sce17
-rwxr-xr-x24/CH26/EX26.4/Example26_4_result.txt5
-rwxr-xr-x24/CH26/EX26.5/Example26_5.sce15
-rwxr-xr-x24/CH26/EX26.5/Example26_5_result.txt3
-rwxr-xr-x24/CH26/EX26.6/Example26_6.sce38
-rwxr-xr-x24/CH26/EX26.6/Example26_6_result.txt17
12 files changed, 146 insertions, 0 deletions
diff --git a/24/CH26/EX26.1/Example26_1.sce b/24/CH26/EX26.1/Example26_1.sce
new file mode 100755
index 000000000..2f33f1b68
--- /dev/null
+++ b/24/CH26/EX26.1/Example26_1.sce
@@ -0,0 +1,11 @@
+exec('electrostatics.sci', -1)
+
+//Given that
+C = 55*10^-15 //in F
+V = 5.3 //in V
+
+//Sample Problem 26-1
+printf("**Sample Problem 26-1**\n")
+Q = C*V
+n = Q/e
+printf("The number of excess electron is equal to %e", n) \ No newline at end of file
diff --git a/24/CH26/EX26.1/Example26_1_result.txt b/24/CH26/EX26.1/Example26_1_result.txt
new file mode 100755
index 000000000..34af00b1f
--- /dev/null
+++ b/24/CH26/EX26.1/Example26_1_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 26-1**
+The number of excess electron is equal to 1.821875e+006 \ No newline at end of file
diff --git a/24/CH26/EX26.2/Example26_2.sce b/24/CH26/EX26.2/Example26_2.sce
new file mode 100755
index 000000000..a6e443d7a
--- /dev/null
+++ b/24/CH26/EX26.2/Example26_2.sce
@@ -0,0 +1,20 @@
+exec('electrostatics.sci', -1)
+
+//Given that
+C1 = 12 //in uF
+C2 = 5.30 //in uF
+C3 = 4.50 //in uF
+V = 12.5 //in Volts
+
+//Sample Problem 26-2a
+printf("**Sample Problem 26-2a**\n")
+C12 = C1 + C2 //in series
+C123 = C12*C3/(C12 + C3) //in parallel
+printf("The equivalent capacitance for the given circuit is %fuF\n", C123)
+
+//Sample Problem 26-2b
+printf("\n**Sample Problem 26-2b**\n")
+Q123 = C123*V
+Q12 = Q123 //in series
+Q1 = Q12*C1/(C1+C2)
+printf("The charge on the capacitor C1 is equal to %fuC", Q1) \ No newline at end of file
diff --git a/24/CH26/EX26.2/Example26_2_result.txt b/24/CH26/EX26.2/Example26_2_result.txt
new file mode 100755
index 000000000..2163ceac1
--- /dev/null
+++ b/24/CH26/EX26.2/Example26_2_result.txt
@@ -0,0 +1,5 @@
+**Sample Problem 26-2a**
+The equivalent capacitance for the given circuit is 3.571101uF
+
+**Sample Problem 26-2b**
+The charge on the capacitor C1 is equal to 30.963303uC \ No newline at end of file
diff --git a/24/CH26/EX26.3/Example26_3.sce b/24/CH26/EX26.3/Example26_3.sce
new file mode 100755
index 000000000..22079f94e
--- /dev/null
+++ b/24/CH26/EX26.3/Example26_3.sce
@@ -0,0 +1,11 @@
+//Given that
+C1 = 3.55 //in uF
+Vo = 6.30 //in Volts
+C2 = 8.95 //in uF
+
+//Sample Problem 26-3
+printf("**Sample Problem 26-3**\n")
+qT = C1*Vo //Total charge
+q1 = qT*C1/(C1+C2) //in parallel
+V = q1/C1
+printf("The final potential difference between each capacitor is equal to %fV", V) \ No newline at end of file
diff --git a/24/CH26/EX26.3/Example26_3_result.txt b/24/CH26/EX26.3/Example26_3_result.txt
new file mode 100755
index 000000000..6357bce74
--- /dev/null
+++ b/24/CH26/EX26.3/Example26_3_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 26-3**
+The final potential difference between each capacitor is equal to 1.789200V \ No newline at end of file
diff --git a/24/CH26/EX26.4/Example26_4.sce b/24/CH26/EX26.4/Example26_4.sce
new file mode 100755
index 000000000..2a4e2a617
--- /dev/null
+++ b/24/CH26/EX26.4/Example26_4.sce
@@ -0,0 +1,17 @@
+exec('electrostatics.sci', -1)
+
+//Given that
+R = 6.85*10^-2 //in m
+q = 1.25*10^-9 //in C
+
+//Sample Problem 26-4a
+printf("**Sample Problem 26-4a**\n")
+C = 4*%pi*Eo*R
+U = q^2/(2*C)
+printf("The electric energy stored is equal to %eJ\n", U)
+
+//Sample Problem 26-4b
+printf("\n**Sample Problem 26-4b**\n")
+E = coulomb(q, 1, R)
+u = 1/2*Eo*E^2
+printf("The energy density is equal to %eJ/m^3", u) \ No newline at end of file
diff --git a/24/CH26/EX26.4/Example26_4_result.txt b/24/CH26/EX26.4/Example26_4_result.txt
new file mode 100755
index 000000000..d0b7dc345
--- /dev/null
+++ b/24/CH26/EX26.4/Example26_4_result.txt
@@ -0,0 +1,5 @@
+**Sample Problem 26-4a**
+The electric energy stored is equal to 1.025525e-007J
+
+**Sample Problem 26-4b**
+The energy density is equal to 2.539012e-005J/m^3 \ No newline at end of file
diff --git a/24/CH26/EX26.5/Example26_5.sce b/24/CH26/EX26.5/Example26_5.sce
new file mode 100755
index 000000000..530b70bee
--- /dev/null
+++ b/24/CH26/EX26.5/Example26_5.sce
@@ -0,0 +1,15 @@
+exec('electrostatics.sci', -1)
+
+//Given that
+C = 13.5*10^-12 //in F
+V = 12.5 //in Volts
+x = 6.50
+
+//Sample Problem 26-5
+printf("**Sample Problem 26-5**\n")
+q = C*V
+Ui = q^2/(2*C)
+printf("The initial stored energy is equal to %eJ\n", Ui)
+C = x*C
+Uf = q^2/(2*C)
+printf("The energy stored after the slab is inserted is equal to %eJ", Uf) \ No newline at end of file
diff --git a/24/CH26/EX26.5/Example26_5_result.txt b/24/CH26/EX26.5/Example26_5_result.txt
new file mode 100755
index 000000000..ee5eb83fd
--- /dev/null
+++ b/24/CH26/EX26.5/Example26_5_result.txt
@@ -0,0 +1,3 @@
+**Sample Problem 26-5**
+The initial stored energy is equal to 1.054688e-009J
+The energy stored after the slab is inserted is equal to 1.622596e-010J \ No newline at end of file
diff --git a/24/CH26/EX26.6/Example26_6.sce b/24/CH26/EX26.6/Example26_6.sce
new file mode 100755
index 000000000..6823913c5
--- /dev/null
+++ b/24/CH26/EX26.6/Example26_6.sce
@@ -0,0 +1,38 @@
+exec('electrostatics.sci', -1)
+
+//Given that
+A = 115*10^-4 //in m^2
+d = 1.24*10^-2 //in meter
+Vo = 85.5 //in Volts
+b = 0.780*10^-2 //in meter
+x = 2.61
+
+//Sample Problem 26-6a
+printf("**Sample Problem 26-6a**\n")
+Co = A*Eo/d
+printf("The capacitance of the plates before the dielectric slab is inserted is equal to %fpF\n", Co*10^12)
+
+//Sample Problem 26-6b
+printf("\n**Sample Problem 26-6b**\n")
+Q = Co*Vo
+printf("Free charge on the plates is equal to%fpC\n", Q*10^12)
+
+//Sample Problem 26-6c
+printf("\n**Sample Problem 26-6c**\n")
+E = Q/(A*Eo)
+printf("The electric field is equal to %fV/m\n", E)
+
+//Sample Problem 26-6d
+printf("\n**Sample Problem 26-6d**\n")
+E1 = Q/(A*Eo*x)
+printf("The electric field in dielectric slab is equal to %fV/m\n", E1)
+
+//Sample Problem 26-6e
+printf("\n**Sample Problem 26-6e**\n")
+V = E*(d-b) + E1*b
+printf("The new potential difference is equal to %fV\n", V)
+
+//Sample Problem 26-6f
+printf("\n**Sample Problem 26-6f**\n")
+C = Q/V
+printf("The new capacitance is equal to %fpF", C*10^12) \ No newline at end of file
diff --git a/24/CH26/EX26.6/Example26_6_result.txt b/24/CH26/EX26.6/Example26_6_result.txt
new file mode 100755
index 000000000..70f2e3fba
--- /dev/null
+++ b/24/CH26/EX26.6/Example26_6_result.txt
@@ -0,0 +1,17 @@
+**Sample Problem 26-6a**
+The capacitance of the plates before the dielectric slab is inserted is equal to 8.207661pF
+
+**Sample Problem 26-6b**
+Free charge on the plates is equal to701.755040pC
+
+**Sample Problem 26-6c**
+The electric field is equal to 6895.161290V/m
+
+**Sample Problem 26-6d**
+The electric field in dielectric slab is equal to 2641.824249V/m
+
+**Sample Problem 26-6e**
+The new potential difference is equal to 52.323971V
+
+**Sample Problem 26-6f**
+The new capacitance is equal to 13.411731pF \ No newline at end of file