1 files changed, 41 insertions, 0 deletions
diff --git a/1919/CH9/EX9.11/Ex9_11.sce b/1919/CH9/EX9.11/Ex9_11.sce
new file mode 100755
index 000000000..0ecc3d561
--- /dev/null
+++ b/1919/CH9/EX9.11/Ex9_11.sce
@@ -0,0 +1,41 @@
+
+// Theory and Problems of Thermodynamics
+// Chapter 9
+// Air_water Vapor Mixtures
+// Example 11
+
+clear ;clc;
+
+//Given data
+RH1 = 0.8               // relative humidity moist air entering
+T1 = 308.15             // Temp of air entering cooling device in K
+P = 101.325             // pressure of entering air in kPa
+RH4 = 0.4               // relative humidity moist air leaving
+T4 = 293.15             // temperature at air required to leave in K
+m = 2                   // flowrate dry air in kg/s
+
+
+// data from psychometric chart
+SH1 = 0.029             // in kg H2O/kg air
+h1 = 110                // in kJ/kg air
+SH4 = 0.0055            // in kg H2O/kg air
+h4 = 34                 // in kJ/kg air
+SH2 = SH4
+RH2 = 1
+h2 = 19                 // in kJ/kg air
+T2 = 278.15             // in K
+hw3 = 20.97             // at 5 degree C in kJ/kg
+
+// masss balance for H2O: ma1*SH1 = ma2*SH2 + mw3
+mw3 = m*(SH1-SH2)         // amount of water condensed in kg/s
+
+// Energy balance: ma1*h1 = ma2*h2 + mw3*hw3 + Qc
+Qc = m*(h1-h2) - mw3*hw3      // in kJ/s
+
+Qh = m*(h4-h2)
+
+
+// Output Results
+mprintf('The amount of water condensed in refrigeration unit = %4.3f kg/s' , mw3);
+mprintf('\n The rate of cooling required in refrigeration unit  = %2.0f kW' , Qc);
+mprintf('\n The rate of heating required in refrigeration unit  = %2.0f kW' , Qh);