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+clc
+clear
+//INPUT DATA
+cp=1.005;//specific pressure
+cv=42000;//specific volume
+R=0.287;//gas constant
+g=1.4;//constant
+t1=300;//temperature in K
+t3=1000;//temperature in K
+Rp=5;//Pressure ratio
+ma=42.93;//mass of air
+mf=0.5;//mass of fuel
+nc=0.8;//compressor efficiency
+nt=0.85;//turbine efficiency
+
+//CALCULATIONS
+t2=t1*(Rp^((g-1)/g));//Temperature in K
+t4=t3/(Rp^((g-1)/g));//Temperature in K
+t21=t1+((t2-t1)/nc);//Temperature in K
+t41=t3-((t3-t4)*nt);//Temperature in K
+wna=-ma*cp*(t21-t1)+(ma+mf)*(t3-t41);//Actual power available in kJ
+ng=(wna/(mf*cv))*100;//Actual thermal efficiency in percentage
+
+//OUTPUT
+printf('(a)Actual power available is %3.2f kJ \n (b)Actual thermal efficiency is %3.2f percentage',wna,ng)
+