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+// Example6.9  // determine Vo when 1) VI1 = 2 V VI2 = -2 V and 2) VI1 = 2 V VI2 = 2 V
+//                                      and common mode rejection ratio CMRR
+clc;
+clear;
+close;
+R1 = 10*10^3 ; // ohm
+R2 = 20*10^3 ; // ohm
+R3 = 10*10^3 ; // ohm
+R4 = 22*10^3 ; // ohm
+
+
+// the output of the difference amplifier is given by
+// Vo = (((R4)/(R3+R4))*(((1+(R2/R1))*VI2))-((R2/R1)*VI1));
+
+// Case 1 when VI1 = 2 V VI2 = -2 V
+VI1 = 2 ;
+VI2 = -2 ;
+
+Vo = (((R4)/(R3+R4))*(((1+(R2/R1))*VI2))-((R2/R1)*VI1));
+disp('The output of the difference amplifier is  = '+string(Vo)+' V ');
+
+// case 2 when VI1 = 2 V VI2 = 2 V
+VI1 = 2 ;
+VI2 = 2 ;
+
+Vo = (((R4)/(R3+R4))*(((1+(R2/R1))*VI2))-((R2/R1)*VI1));
+disp('The output of the difference amplifier is  = '+string(Vo)+' V ');
+
+// the common mode input of difference amplifier is given by
+VCM = (VI2+VI1)/2 ;
+disp('the common mode input of difference amplifier is = '+string(VCM)+' ');
+
+// the common mode gain ACM of difference amplifier is given by
+ACM = Vo/VCM
+disp('the common mode gain ACM of difference amplifier is = '+string(ACM)+' ');
+
+// the differential gain of the difference amplifier is given 
+Ad = R2/R1 ; 
+disp('the differential gain of the difference amplifier is = '+string(Ad)+' ');
+
+// the common mode rejection ratio CMRR is 
+CMRR = abs(Ad/ACM);
+disp('The common mode rejection ratio CMRR is  = '+string(CMRR)+' ');
+
+// in decibal it can be expressed as
+CMRR = 20*log10(CMRR);
+disp('The common mode rejection ratio CMRR in decibel is  = '+string(CMRR)+' dB ');
+