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+// Example 9.1
+// Zero-Input Response of an RL circuit
+// From figure 9.5
+L=60*10^-3;
+R_eq=40+10;// Equivalent resistance
+tau=L/R_eq; // Time constant
+// Let us denote y(0^-) by y_bef and y(0^+) by y_aft
+i_bef= 25/10; // t<0 , under steady state conditions
+// form the continuity equation of inductor current we get
+i_aft=i_bef;
+v_bef=25;
+t=0:0.0001:0.01;
+i=i_aft*%e^(-t/tau); // t>0
+v=-40*i; // t>0
+subplot(2,1,1)
+plot(t,i,'r');
+xlabel('t')
+ylabel('i(t)')
+title('Current Waveform of inductor')
+subplot(2,1,2)
+plot(t,v,'-g')
+xlabel('t')
+ylabel('v(t)')
+title('Voltage Waveform across 40-Ohm resistance')
+