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+// Example 1.7
+// A Transistor Circuit
+// Enclosing the Transistor with a supernode and using KCL we get i_b as
+i_b=(10.5*10^-3)-(10*10^-3);
+// Applying KVL for the Loop CEBC we get
+v_ce=1+6;
+i_4=10*10^-3; // from the figure 1.29
+v_3=1; // from the figure 1.29
+// at node D
+i_1=i_4+(2*10^-3);
+// at node A
+i_3=(2*10^-3)-i_b;
+// Loop DCEFD
+v_4=9-v_ce
+// Loop AFDA
+v_2=v_3-9;
+disp(i_b,"Current in the Base of the Transistor,i_b(in Amps)=")
+disp(v_ce," Volatge across Collector-Emitter terminal,v_ce(in Volts)=")
+disp(i_4,"current through the Branch DC, i_4(in Amps)=")
+disp(v_3,"Voltage across the branch AF,v_3(in Volts)") 
+disp(i_1,"Current through the Voltage source,i_1(in Amps)=")
+disp(i_3,"current through the branch AF,i_3(in Amps)=")
+disp(v_4,"Voltage across the Branch DC,v_4(in Volts)=")
+disp(v_2,"Voltage across the Current Source,v_2(in Volts)=")