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+//ques-5.15
+//Calculating solubility product of AgCl
+clc
+S=0.00179;//solubility of AgCl (in g/L)
+S=(S/170)*100000;//solubility (in mol/L x10^-5)
+K=S^2;//solubility product (x10^-10)
+printf("The solubility product of given AgCl is %.4f x 10^-10 mol^2/L^2.",K);