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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
commit7bc77cb1ed33745c720952c92b3b2747c5cbf2df (patch)
tree449d555969bfd7befe906877abab098c6e63a0e8 /3862/CH4/EX4.20
parentd1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 (diff)
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Added new codeHEADmaster
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+clear
+//Each angle is divided into two rectangles
+
+//variable declaration
+
+A1=600.0*15.0 //Area of 1,mm^2
+A2=140.0*10.0 //Area of 2,mm^2
+A3=150.0*10.0
+A4=400.0*20.0
+A=A1+A2*2+A3*2+A4 //Total area,mm^2
+
+//The distance of the centroidal axis from the bottom fibres of section
+
+Y1=320.0
+Y2=100.0
+Y3=25.0
+Y4=10.0
+
+yc=(A1*Y1+2*A2*Y2+A3*Y3*2+A4*Y4)/A
+printf("\n yc")
+//Now, Moment of inertia about the centroidalaxis=Sum of the moment of inertia of the individual rectangles
+
+Ixx=(15.0*(600**3)/12.0)+(A1*((yc-320)**2))+((10.0*(140**3.0)/12.0)+(A2*((yc-100.0)**2)))*2+((150*(10**3)/12.0)+(A3*((yc-15.0)**2)))*2+(400.0*(20.0**3.0)/12.0)+(A4*((yc-10.0)**2))
+
+
+printf("\n Ixx= %0.1f mm^4",Ixx)