Added new codeHEADmaster

1 files changed, 39 insertions, 0 deletions

diff --git a/3862/CH2/EX2.29/Ex2_29.sce b/3862/CH2/EX2.29/Ex2_29.sce
new file mode 100644
index 000000000..21a9df515
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+++ b/3862/CH2/EX2.29/Ex2_29.sce
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+clear
+//
+
+
+// Let O1 and O2 be the centres of the first and second spheres. Drop perpendicular O1P to the horizontal line through O2. show free body diagram of the sphere 1 and 2, respectively. Since the surface of contact are smooth, reaction of B is in the radial direction, i.e., in the direction O1O2. Let it make angle a with the horizontal. Then,
+
+//Variable declaration
+
+W=100.0                     //weight of spheres,N
+
+r=100.0                     //radius of spheres,mm
+
+d=360.0                     // horizontal channel having vertical walls, the distance b/w,mm
+
+O1A=100.0
+O2D=100.0
+O1B=100.0
+BO2=100.0
+
+O2P=360.0-O1A-O2D
+O1O2=O1B+BO2
+
+alpha=acos(O2P/O1O2)
+
+//////sum of vertical Fy & sum of horizontal forces Fx is zero
+//Assume direction of Fx is right
+//Assume direction of Fy is up
+RB=W/sin(alpha)
+RA=RB*cos(alpha)
+printf("\n RB= %0.2f  N",RB)
+printf("\n RA= %0.2f  N",RA)
+
+RC=100+RB*sin(alpha)
+
+RD=RB*cos(alpha)
+
+printf("\n RC= %0.0f  N",RC)
+
+printf("\n RD= %0.2f  N",RD)