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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3681/CH10/EX10.15/Ex10_15.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3681/CH10/EX10.15/Ex10_15.sce')
| -rw-r--r-- | 3681/CH10/EX10.15/Ex10_15.sce | 19 |
1 files changed, 19 insertions, 0 deletions
diff --git a/3681/CH10/EX10.15/Ex10_15.sce b/3681/CH10/EX10.15/Ex10_15.sce new file mode 100644 index 000000000..fe94cc837 --- /dev/null +++ b/3681/CH10/EX10.15/Ex10_15.sce @@ -0,0 +1,19 @@ +// Calculating the number of stator turns per phase
+clc;
+disp('Example 10.15, Page No. = 10.44')
+// Given Data
+// 3 phase star connected induction motor
+P = 75;// Power rating (in kw)
+V = 3000;// Voltage rating
+f = 50;// Frequency (in Hz)
+p = 8;// Number of poles
+AT60 = 500;// mmf required for flux density at 30 degree from pole axis
+Kws = 0.95;// Winding factor
+e = 0.94;// Full load efficiency
+pf = 0.86;// Full load power factor
+// Calculation of the number of stator turns per phase
+I = P*10^(3)/(3^(1/2)*V*e*pf);// Full load current (in ampere)
+Im = 0.35*I;// Magnetizing current (in Ampere). Since magnetizing current is 35% of full load current
+Ts = 0.427*p*AT60/(Kws*Im);// Stator turns per phase
+disp(Ts,'Stator turns per phase =');
+//in book answer is 288. The answers vary due to round off error
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