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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 2_10 page no:74
+clc
+//mesh equation for the given circuit is
+resistance=[15,-10,-5;-15,12,6;0,1,-1]
+U=[40.0005,23.3326,-11.3332]
+II=inv(resistance)'*U'//calculating current I1 I2 I3
+current=II(1,1)-II(3,1)
+disp(current,"current flowing through 5 ohms (in ampere)")