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authorpriyanka2015-06-24 15:03:17 +0530
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+//Initilization of variables
+m=5 //kg
+d=6 //m
+theta1=30 //degrees
+theta2=10 //degrees
+u=0.2 //coefficient of friction
+g=9.8 //m/s^2
+F=70 //N
+//Calculations
+//Using free body diagram
+Na=m*g*cosd(theta1)-(F*sind(theta2)) //N
+//work done by each force
+W=[F*cosd(theta2),-m*g*sind(theta1),0,-u*Na*d] //N.m
+//Total Work Done
+W_tot=W(1)+W(2)+W(3)+W(4) //N.m
+//Using resultant
+R=F*cosd(theta2)-(u*Na)-(m*g*sind(theta1)) //N
+W_d=R*d //N.m (Work Done)
+//Result
+clc
+printf('The work done is %f N.m',W_d)