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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Determine the induced voltage in the telephone line
+clear;
+clc;
+
+//soltion
+//given
+Vl=132*1000;//Volt
+P=28*10^6;//load in kw
+pf=0.85;//power factor
+f=50;//Hz
+l=200;//length of the line
+r=0.005;//radius of conductor
+hA=20;//height of the line
+Ao=4*sqrt(3)/2;
+dAP=Ao+5;
+dAQ=dAP+1;;
+dBP=sqrt(5*5+2*2);
+dBQ=sqrt(6*6+2*2);
+Ma=0.2*log(dAQ/dAP);
+Mb=0.2*log(dBQ/dBP);
+M=(Mb-Ma)*10^-3;
+I=P/(sqrt(3)*Vl*pf);
+Vm=2*%pi*f*M*I;
+printf("For 200 km line induced voltage= %.1f volts\n",Vm*l);
+Va=Vl/sqrt(3);
+Vb=Va;
+Vpa=Va*log((2*(hA+Ao)-dAP)/dAP)/log((2*(hA+Ao)-r)/r);
+Vpb=Vb*log((2*(hA+Ao)-dBP)/dBP)/log((2*(hA+Ao)-r)/r);
+Vp=Vpb-Vpa;
+printf("The potential of telephone line= %d volts",Vp);
+//the ans in the book is Vm= 90.4 volts and Vp=4396 because of using round off in some values