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+//Example6.10  // To determine the range of the differential voltage gain

+clc;

+clear;

+close;

+//R1 = 1 K ohm to 25 K ohm ;

+R2 = 50 ; // K ohm

+R3 = 10 ;  // K ohm

+R4 = 10 ; // K ohm

+

+// the output of instrumentation amplifier is given by

+//Vo = (R4/R3)*(1+(2*R2/R1))*(VI@-VI1);

+

+// the differential voltage gain of the instrumentation amplifier can be written as

+//Av = (Vo/(VI2-VI1)) = (R4/R3)*(1+(2R2/R1));

+

+// For R1 = 1 K ohm   the maximum differential voltage gain of the instrumentation amplifier is

+R1 = 1 ; // K ohm

+Av = (R4/R3)*(1+(2*R2/R1));

+disp('the maximum differential voltage gain of the instrumentation amplifier is = '+string(Av)+ ' ');

+

+// For R1 = 25 K ohm   the mminimum differential voltage gain of the instrumentation amplifier is

+R1 = 25 ; // K ohm

+Av = (R4/R3)*(1+(2*R2/R1));

+disp('the minimum differential voltage gain of the instrumentation amplifier is = '+string(Av)+ ' ');

+

+disp(' the range of the differential voltage gain of the instrumentation amplifier is ');

+disp('                    5 <= Av <= 101 ');