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authorpriyanka2015-06-24 15:03:17 +0530
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+//Basic Circuit Concepts
+//page no-1.17
+//example1.12
+disp("Applying KVL to the circuit :");
+disp("50 - 5*I - 1.2*I - 16 = 0")
+I=(50-16)/6.2;
+printf("I= %.2f Amp", I);
+P=50*I;
+printf("\nPower delivered 50 V source = 50 * 5.48= %.2f W", P); \ No newline at end of file