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+//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
+//Example 10
+
+disp("CHAPTER 2");
+disp("EXAMPLE 10");
+
+//Equations
+//If z1, z2 || then net impedance is Z=z1.z2/(z1+z2)
+//V=IZ
+//Power drawn is = V.I. cos (phi)
+
+//VARIABLE INITIALIZATION
+v=230;                           //in Volts
+z1=3+(%i*4);                     //impedance in rectangular form in Ohms
+z2=6+(%i*8);                     //impedance in rectangular form in Ohms
+
+//SOLUTION
+function [z,angle]=rect2pol(x,y);
+z=sqrt((x^2)+(y^2));             //z is impedance & the resultant of x and y
+angle=atan(y/x)*(180/%pi);       //to convert the angle from radians to degrees
+endfunction;
+
+[z1,angle1]=rect2pol(3,4);
+[z2,angle2]=rect2pol(6,8);
+
+z=(z1*z2)/(z1+z2); 
+I=v/z;
+angle=-angle1;                   //as angle1=angle2
+//
+disp(sprintf("The current drawn from the circuit is %2.0f Amp",I));
+disp(sprintf("The net current lags net voltage by %4.2f and ckt is inductive in nature",-angle));
+p=v*I*cos(angle*%pi/180);        //to convert the angle from degrees to radians
+disp(sprintf("The power drawn from the source is %5.3f kW",p/1000));
+
+//END