From b3f3a8ecd454359a2e992161844f2fb599f8238a Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Fri, 4 Oct 2019 12:24:07 +0530
Subject: Initial commit/added all books

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 .../CH9/EX9.1/Ex9_1.R                              | 40 ++++++++++++++++++++++
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 create mode 100644 Numerical_Methods_by_E_Balaguruswamy/CH9/EX9.1/Ex9_1.R

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diff --git a/Numerical_Methods_by_E_Balaguruswamy/CH9/EX9.1/Ex9_1.R b/Numerical_Methods_by_E_Balaguruswamy/CH9/EX9.1/Ex9_1.R
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+#Example 1     Chapter 9       Page no.: 277
+# Polynomial Forms
+
+#Consider the power form of p(x) for n=1, p(x)=a0 + a1*X, 
+
+#Given that p(100)= +3/7, p(101)= -4/7
+p_100= 3/7
+p_101= -4/7
+
+
+cat(paste(p_100,"is the given p(100) and",p_101,"is the given p(101)"))
+
+
+A<- matrix(c(1,100,1,101), nrow=2,ncol=2, byrow=T)
+A
+b<-matrix(c(p_100,p_101))
+b
+sol= solve(A,b)
+a0<-round(sol[1], 1)
+a1<-sol[2]
+print(paste("a0 is :",a0 ))
+print(paste("a1 is :",a1 ))
+
+#comparing calculated value with given ones
+print("power form equation : ")
+substitute(a0+a1*x, list(a0=sol[1], a1=sol[2]))
+
+#substitue x=100
+x1<-100
+substitute(a0+a1*x, list(a0=a0, a1=a1, x=x1))
+New_p100 = a0 + (a1*x1)
+#substitute x=101
+x2<-101
+substitute(a0+a1*x, list(a0=a0, a1=a1, x=x2))
+New_p101= a0 + (a1*x2)
+
+cat(paste(signif(New_p100,5),"is the new p(100) and", signif(New_p101,5),"is the new p(101)"))
+
+
+
-- 
cgit