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{
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"name": "",
"signature": "sha256:1d0e8ca0a27c4b0cb17e7318d009efc3241a84a31e3f27c8ca705f6cb5276ce4"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 02:Natural Soil Deposits and Subsoil Exploration"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.1:Pg-109"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 2.1\n",
"import matplotlib.pyplot as plt\n",
"import numpy\n",
"import math\n",
"Distance=[2.5,5,7.5,10,15,20,25,30,35,40,50];\n",
"Time=(10**(-3))*numpy.array([11.2,23.3,33.5,42.4,50.9,57.2,64.4,68.6,71.1,72.1,75.5])\n",
"#part1\n",
"distance=5.25; # in meter\n",
"time=23e-3; # in second\n",
"v1=distance/time;\n",
"print round(v1,2),\"is speed in m/s\"\n",
"#part2\n",
"distance=11; # in meter\n",
"time=13.5e-3;# in second\n",
"v2=distance/time;\n",
"print round(v2,2),\" is speed in m/s\"\n",
"#part3\n",
"distance=14.75;# in meter\n",
"time=3.5e-3;# in second\n",
"v3=distance/time;\n",
"print round(v3,2),\"speed in m/s\"\n",
"plt.plot(Distance,Time);\n",
"plt.title(\"distance vs time\")\n",
"plt.xlabel(\"Distance in m\")\n",
"plt.ylabel(\"time in s\")\n",
"plt.show()\n",
"#part4\n",
"xc=10.4;\n",
"Ta=65e-3;\n",
"Z1=1/2.0*math.sqrt((v2-v1)/(v2+v1))*xc;\n",
"print round(Z1,2),\" is thickness of layer 1 in m\"\n",
"Z2=1/2.0*(Ta-2*Z1*math.sqrt(v3**2-v1**2)/v3/v1)*v3*v2/math.sqrt(v3**2-v2**2);\n",
"print round(Z2,2),\" is thickness of layer 2 in m\"\n",
"\n",
"# the answers are slightly different in textbook due to approximation while here answers are precise"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"228.26 is speed in m/s\n",
"814.81 is speed in m/s\n",
"4214.29 speed in m/s\n",
"3.9"
]
},
{
"output_type": "stream",
"stream": "stdout",
"text": [
" is thickness of layer 1 in m\n",
"12.82 is thickness of layer 2 in m\n"
]
}
],
"prompt_number": 10
}
],
"metadata": {}
}
]
}
|
