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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 18 Fibre Optics"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.1 Page no 859"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"c=3*10**8 #velocity of light\n",
"f=4.4*10**14 #frequency of red light\n",
"f1=7.0*10**14 #frequency of violet light\n",
"\n",
"#calculation\n",
"h1=c/f #wavelength of red light\n",
"h2=c/f1 #wavelength of violet light\n",
"\n",
"#result\n",
"print\"wavelenght for red= \",round(h1,9),\"m\"\n",
"print\"wavelngth for violet= \",round(h2,8),\"micron\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"wavelenght for red= 6.82e-07 m\n",
"wavelngth for violet= 4.3e-07 micron\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.2 Page no 862"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"n1=1.535 #refractive index of fibre optics\n",
"n2=1.490 #refractive index of cladding\n",
"\n",
"#calculation\n",
"import math\n",
"x=(n1**2)-(n2**2)\n",
"y=math.sqrt(x) #numerical aperture\n",
"z=math.asin(y)*180/3.14 #theta\n",
"\n",
"#result\n",
"print\"NA = \",round(y,3)\n",
"print\"(theta)in(max) = \",round(z,1),\"degree\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"NA = 0.369\n",
"(theta)in(max) = 21.7 degree\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.3 Page no 868"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"w=22 #spectral width of LED\n",
"l=2 #length of fibre\n",
"d=95 #dispersion value\n",
"p=d*w #pulse dispersion\n",
"pt=p*l #total pulse dispersion\n",
"\n",
"#result\n",
"print\"pulse dispersion = \",p,\"ps/km\"\n",
"print\"total pulse dispersion = \",pt,\"ps/km\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"pulse dispersion = 2090 ps/km\n",
"total pulse dispersion = 4180 ps/km\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.4 Page no 885"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"d=30 #length of fibre cable\n",
"l=0.4 #loss\n",
"\n",
"#calculation\n",
"T=d*l #total cable loss\n",
"\n",
"#result\n",
"print\"total cable loss = \",T,\"dB\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"total cable loss = 12.0 dB\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.5 Page no 887"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"b=565 #Line bit rate of fibre 1\n",
"c=3.5 #Cable dispersion of fibre 1\n",
"t=4 #Transmitter spectral width of fibre 1\n",
"b1=1130 #Line bit rate of fibre 2\n",
"c1=3.5 #Cable dispersion of fibre 2\n",
"t1=2 #Transmitter spectral width of fibre 2\n",
"x=440000 #assumed gaussian constant \n",
"\n",
"#calculation\n",
"L1=x/(b*c*t) #span length in km of fibre 1\n",
"L2=x/(b1*c1*t1) #span length in km of fibre 2\n",
"\n",
"#result \n",
"print\"span lenght of fibre 1= \",round(L1,2),\"Km\"\n",
"print\"span lenght of fibre 2= \",round(L2,2),\"Km\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"span lenght of fibre 1= 55.63 Km\n",
"span lenght of fibre 2= 55.63 Km\n"
]
}
],
"prompt_number": 20
}
],
"metadata": {}
}
]
}
|
