1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
|
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 11 : Conductors and Insulators"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 11_1 Page No. 329"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Circular Area = 25.00 cmils\n"
]
}
],
"source": [
"# What is the area in circular mils of a wire with a diameter of 0.005 in.?\n",
"\n",
"# Given data\n",
"\n",
"Din = 0.005# # Diameter in Inches=0.005 in.\n",
"Dmil = 5# # Diameter in Mils=5 mil.\n",
"\n",
"# 0.005 in. = 5 mil\n",
"# Therefore: Din == Dmil\n",
"\n",
"A = Dmil*Dmil#\n",
"print 'The Circular Area = %0.2f cmils'%A"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 11_2 Page No. 335"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Total Area = 3224.00 cmils\n"
]
}
],
"source": [
"# A stranded wire is made up of 16 individual strands of No. 27 gage wire. What is its equivalent gage size in solid wire?\n",
"\n",
"# Given data\n",
"\n",
"N = 16# # No. of strands=16\n",
"A27 = 201.5 # Circular area of No. 27 Guage wire=201.5 cmils\n",
"\n",
"A = N*A27#\n",
"print 'The Total Area = %0.2f cmils'%A"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 11_3 Page No. 340"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Resistance of 100 ft of No. 20 gage Copper Wire = 1.02 ohms\n"
]
}
],
"source": [
"# How much is the resistance of 100 ft of No. 20 gage copper wire?\n",
"\n",
"# Given data\n",
"\n",
"roh = 10.4# # roh or specific resistance=10.4 (for Copper)\n",
"l = 100.# # Lenght=100 feet\n",
"A = 1022# # Area of No. 20 Gage=1022 cmil\n",
"\n",
"R = roh*(l/A)#\n",
"print 'The Resistance of 100 ft of No. 20 gage Copper Wire = %0.2f ohms'%R"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 11_4 Page No. 342"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Resistance of 100 ft of No. 20 gage Copper Wire = 2.04 ohms\n"
]
}
],
"source": [
"# How much is the resistance of 100 ft of No. 23 gage copper wire?\n",
"\n",
"# Given data\n",
"\n",
"roh = 10.4# # roh or specific resistance=10.4 (for Copper)\n",
"l = 100# # Lenght=100 feet\n",
"A = 509.5# # Area of No. 23 Gage=509.5 cmil\n",
"\n",
"R = roh*(l/A)#\n",
"print 'The Resistance of 100 ft of No. 20 gage Copper Wire = %0.2f ohms'%R"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 11_5 Page No. 344"
]
},
{
"cell_type": "code",
"execution_count": 9,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Resistance of a Slab of Germanium = 11.00 ohms\n"
]
}
],
"source": [
"# How much is the resistance of a slab of germanium 0.2 cm long with a crosssectional area of 1 sqcm?\n",
"\n",
"# Given data\n",
"\n",
"roh = 55.0# # roh or specific resistance=55 (for Germanium)\n",
"l = 0.2*10**-2# # Lenght=100 feet\n",
"A = 1.0*10**-2# # Area=1 sqcm\n",
"\n",
"R = roh*(l/A)#\n",
"print 'The Resistance of a Slab of Germanium = %0.2f ohms'%R"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example No. 11_6 Page No. 344"
]
},
{
"cell_type": "code",
"execution_count": 11,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The Resistance at 120°C = 21.00 ohms\n"
]
}
],
"source": [
"# A tungsten wire has a 14-Ohms\u0002 R at 20°C. Calculate its resistance at 120°C.\n",
"\n",
"# Given data\n",
"\n",
"Tmax = 120.# # Temp(max)=120 degree Centigrates\n",
"Tmin = 20.# # Temp(min)=20 degree Centigrates\n",
"Ro = 14.# # Wire Resistance=14 Ohms\n",
"alpha = 0.005# # Aplha=0.005 (for Tungsten)\n",
"\n",
"delta = Tmax-Tmin#\n",
"\n",
"Rt = Ro+Ro*(alpha*delta)#\n",
"print 'The Resistance at 120°C = %0.2f ohms'%Rt"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 2",
"language": "python",
"name": "python2"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 2
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython2",
"version": "2.7.9"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|