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{
"metadata": {
"celltoolbar": "Raw Cell Format",
"name": "",
"signature": "sha256:a21e16171dbf63c7ecd113809cbf95f48b678483e5d0f4506fd5f7c0d330d29a"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 3: Optical Sources"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.1,Page number 67"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#given\n",
"\n",
"Pin=1; #microW\n",
"W=15; #in degree\n",
"NA=math.sin(W*math.pi/180);\n",
"NAA=0.26; #NA=0.2588190 which is rounded off\n",
"C_c=(NAA)**2;\n",
"print\"Coupling coefficient is \",C_c;\n",
"Pf=C_c*Pin;\n",
"print\"Power coupled into fiber \",Pf*1000,\"nW\\n\";\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Coupling coefficient is 0.0676\n",
"Power coupled into fiber 67.6 nW\n",
"\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.2,Page number 67"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#given\n",
"\n",
"n=0.02; #in percentage\n",
"W=20; #in degree\n",
"Vf=1.5; #in Volts\n",
"If=20; #in mAmps\n",
"Pin=If*Vf;\n",
"print\"Power coupled into fiber ,Pin = \",Pin,\"mW\";\n",
"\n",
"Po=n*Pin;\n",
"print\"Output Power of the optical source is \",Po,\"mW\";\n",
"\n",
"#from nc=20 degree\n",
"C_c=(math.sin(W*math.pi/180))**2;\n",
"Pf=C_c*Po\n",
"print\"Optical power coupled into fibre is ,Pf = \",round(Pf*1000,4),\"microW\";\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Power coupled into fiber ,Pin = 30.0 mW\n",
"Output Power of the optical source is 0.6 mW\n",
"Optical power coupled into fibre is ,Pf = 70.1867 microW\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.3,Page number 68"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#given\n",
"\n",
"tr=10; #in nsec\n",
"BW=0.35/tr/10**-9;\n",
"print\" Maximum operating bandwidth is \",BW/10**6,\"MHz\\n\"; #divided by 10**6 to convert answer in MHz\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Maximum operating bandwidth is 35.0 MHz\n",
"\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.4,Page number 70"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#given\n",
"\n",
"T=1; #Air\n",
"NA=0.3;\n",
"n0=1;\n",
"#x=y;\n",
"print\"for step index :A=infinite\";\n",
"#for infinite alpha\n",
"#nc=T*(NA/n0)^2*(x/y)^2*(A/(A+2))\n",
"nc=T*(NA/n0)**2*(1)**2*1; # A/(A+2)=1 for A=infinite\n",
"\n",
"print\"Coupling Coefficient,nc = \",nc*100,\"percent\";\n",
"\n",
"print\"for graded index :A=2\";\n",
"A=2;\n",
"#n_c=(T*(NA/n0)^2*(A+(1-(y/x)^2))/(A+2))\n",
"n_c=(T*(NA/n0)**2*(A+(1-(1)**2))/(A+2)) #x/y=1\n",
"print\"Coupling Coefficient,nc = \",n_c*100,\"percent\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"for step index :A=infinite\n",
"Coupling Coefficient,nc = 9.0 percent\n",
"for graded index :A=2\n",
"Coupling Coefficient,nc = 4.5 percent\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.5,Page number 71"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#given\n",
"\n",
"T=1; #Air\n",
"NA=0.3;\n",
"n0=1;\n",
"A=2;\n",
"#y=0.75x;\n",
"print\"for step index :\";\n",
"#for infinite alpha\n",
"#nc=T*(NA/n0)^2*(x/y)^2*(A/(A+2))\n",
"nc=T*(NA/n0)**2*(1/0.75)**2*A/(A+2); #y/x=0.75\n",
"print\"Coupling Coefficient,nc = \",nc*100,\"percent\";\n",
"\n",
"print\"for graded index :A=2\";\n",
"A=2;\n",
"#n_c=(T*(NA/n0)^2*(A+(1-(y/x)^2))/(A+2))\n",
"n_c=(T*(NA/n0)**2*(A+(1-(0.75)**2))/(A+2)) #y/x=0.75\n",
"print\"Coupling Coefficient,nc = \",round(n_c*100,4),\"percent\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"for step index :\n",
"Coupling Coefficient,nc = 8.0 percent\n",
"for graded index :A=2\n",
"Coupling Coefficient,nc = 5.4844 percent\n"
]
}
],
"prompt_number": 15
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.6,Page number 72"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#given\n",
"\n",
"#calculate Tf\n",
"If=85; #in mAmps\n",
"Vf=2.5; #in Volts\n",
"Ta=25; #in deg C\n",
"\n",
"#calculate Tj\n",
"W=150; #in C/W for hermetric led\n",
"Pd=If*Vf;\n",
"Tj=Ta+W*Pd/1000;\n",
"print\"Value of Tj is \",Tj,\"deg C\";\n",
"\n",
"TF=8.01*10**12*math.e**-(8111/(Tj+273));\n",
"print\"Value of TF is \",round(TF,4),\"deg C\";\n",
"\n",
"#calculate RF\n",
"BF=6.5*10**-4; #from table\n",
"QF=0.5; #from table\n",
"EF=1; #from table\n",
"RF=BF*TF*EF*QF*1/10**6;\n",
"print\"Value of RF\",\"{0:.3e}\".format(RF);\n",
"print\"Value of MTBF is \",\"{0:.3e}\".format(1/RF),\"hours\";\n",
"\n",
"#Answer in book is misprint in last line"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Value of Tj is 56.875 deg C\n",
"Value of TF is 167.9406 deg C\n",
"Value of RF 5.458e-08\n",
"Value of MTBF is 1.832e+07 hours\n"
]
}
],
"prompt_number": 20
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.7,Page number 74"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#given\n",
"\n",
"#calculate Tf\n",
"If=120; #in mAmps\n",
"Vf=1.8; #in Volts\n",
"Ta=80; #in deg C\n",
"#calculate Tj\n",
"W=150; #in C/W for hermetric led\n",
"Pd=0.5*If*Vf;\n",
"Tj=75+W*Pd/1000;\n",
"print\"Value of Tj is \",Tj,\"degree cel\";\n",
"TF=8.01*10**12 *math.e**-(8111/(Tj+273));\n",
"print\"Value of TF is \",round(TF,4);\n",
"#calculate RF\n",
"BF=6.5*10**-4; #from table\n",
"QF=0.2; #from table\n",
"EF=0.75; #from table\n",
"RF=BF*TF*EF*QF*1/10**6;\n",
"print\"Value of RF is \",\"{0:.3e}\".format(RF);\n",
"print\"Value of MTBF is \",\"{0:.3e}\".format(1/RF),\"hours\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Value of Tj is 91.2 degree cel\n",
"Value of TF is 1704.4223\n",
"Value of RF is 1.662e-07\n",
"Value of MTBF is 6.018e+06 hours\n"
]
}
],
"prompt_number": 25
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
