{ "cells": [ { "cell_type": "code", "execution_count": 3, "metadata": { "collapsed": true }, "outputs": [], "source": [ "#CHAPTER 2" ] }, { "cell_type": "code", "execution_count": 4, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "the weight is 128.8\n" ] } ], "source": [ "##Example2_1\n", "# Aim:To Find Weight of Body\n", "# Given:\n", "# Mass of the Body:\n", "m=4; #slugs\n", "\n", "# Solutions:\n", "# we know acceleration due to gravity,\n", "g=32.2; #ft/s**2\n", "W=(m*g);\n", "\n", "# Results:\n", "print \"the weight is\",W\n" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " Results: \n", " The specific weight of Body is lb/ft**3. 71.7\n" ] } ], "source": [ "##Example2_2\n", "# Aim:To find the specific weight of a body\n", "# Given:\n", "# Weigth of the Body:\n", "W=129; #lb\n", "# Volume of the Body:\n", "V=1.8; #ft**3\n", "\n", "# Solution:\n", "# we know specific weight,\n", "# gamma=(Weigth of the Body/Volume of the Body)\n", "gamma1=(W/V); #lb/ft^3\n", "# rounding off the above answer\n", "gamma1=round(gamma1)+(round((gamma1-round(gamma1))*10)/10); #lb/ft^3\n", " \n", "# Results:\n", "print \" Results: \"\n", "print \" The specific weight of Body is lb/ft**3.\",gamma1\n" ] }, { "cell_type": "code", "execution_count": 5, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Results: \n", "The specific gravity of air 0.00120512820513\n" ] } ], "source": [ "##Example2_3\n", "# Aim:To find the specific gravity of air at 68 degF\n", "# Given:\n", "# specific weight of air at 68 degF:\n", "gamma_air=0.0752; #lb/ft**3\n", "\n", "\n", "# Solution:\n", "# we know,\n", "# specific gravity of air=(specific weight of air/specific weight of water)\n", "# also we know,specific weight of water at 68 degF,\n", "gamma_water=62.4; #lb/ft**3\n", "SG_air=gamma_air/gamma_water;\n", "\n", "# Results:\n", "print \"Results: \"\n", "print \"The specific gravity of air \",SG_air \n", "\n" ] }, { "cell_type": "code", "execution_count": 9, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Results: \n", "The Density of Body is slugs/ft**3. 2.22222222222\n", "The Density of Body is slugs/ft**3. 2.22360248447\n" ] } ], "source": [ "##Example2_4\n", "# Aim:To find Density of body of Example 2-1 and 2-2\n", "# Given:\n", "# mass of the Body:\n", "m=4; #slugs\n", "# Volume of the Body:\n", "V=1.8; #ft**3\n", "\n", "# Solution:\n", "# we know density,\n", "# rho1=(mass of the Body/Volume of the Body)\n", "rho1=(m/V); #slugs/ft**3\n", "# also density,rho2=(specific weight/acceleration due to gravity)\n", "g=32.2; #ft/s**2\n", "gamma1=71.6; #lb/ft**3\n", "rho2=(gamma1/g); #slugs/ft**3\n", "\n", "# Results:\n", "print \"Results: \"\n", "print \"The Density of Body is slugs/ft**3.\",rho1\n", "print \"The Density of Body is slugs/ft**3.\",rho2\n" ] }, { "cell_type": "code", "execution_count": 10, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " Results: \n", " The pressure on skin diver is % psi. 25.992\n" ] } ], "source": [ "##Example2_5\n", "# Aim:To find pressure on the skin diver\n", "# Given:\n", "# Depth of Water Body:\n", "H=60; #ft\n", "\n", "# Solution:\n", "# specific Weight of water,\n", "gamma1=0.0361; #lb/in**3 \n", "# Conversion: \n", "# 1 feet = 12 inches\n", "# 1 lb/in**2 = 1 psi \n", "# we know pressure,\n", "# p=(specific weight of liquid * liquid column height)\n", "p=(gamma1*H*12); #psi\n", "\n", "# Results:\n", "print \" Results: \"\n", "print \" The pressure on skin diver is % psi.\",p\n", "\n", "\n" ] }, { "cell_type": "code", "execution_count": 12, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " Results: \n", " The Height of water column is ft. 33.7977839335\n" ] } ], "source": [ "##Example2_6\n", "# Aim:To find tube height of a Barometer\n", "# Given:\n", "# liquid used is Water instead of Mercury.\n", "\n", "# Solution:\n", "# specific Weight of water,\n", "gamma1=0.0361; #lb/in**3 \n", "# We also knows Atmospheric Pressure,\n", "p=14.7; #psi\n", "# Conversion: \n", "# 1 feet = 12 inches\n", "# 1 lb/in**2 = 1 psi \n", "# we know pressure,\n", "# p=(specific weight of liquid * liquid column height)\n", "# Therefore,\n", "H=(p/gamma1); #in\n", "# He=Height in Feet.\n", "He=H*0.083; #ft\n", "\n", "# Results:\n", "print \" Results: \"\n", "print \" The Height of water column is ft.\",He\n" ] }, { "cell_type": "code", "execution_count": 13, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " Results: \n", " The Absolute Pressure is psi. 9.7\n" ] } ], "source": [ "##Example2_7\n", "# Aim:To convert given pressure into absolute pressure\n", "# Given:\n", "# Gage Pressure:\n", "Pg=-5; #psi\n", "\n", "# Solution:\n", "# Atmospheric Pressure,\n", "Po=14.7; #psi \n", "# Absolute Pressure(Pa) =Gage Pressure + Atmospheric Pressure\n", "Pa=Pg+Po;\n", "\n", "# Results:\n", "print \" Results: \"\n", "print \" The Absolute Pressure is psi.\",Pa\n" ] }, { "cell_type": "code", "execution_count": 14, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " Results: \n", "The Absolute Pressure is psi. 40.7\n" ] } ], "source": [ "##Example2_8\n", "# Aim:To find absolute pressure on skin diver of Example 2-5\n", "# Given:\n", "# Gage Pressure:\n", "Pg=26; #psi\n", "\n", "# Solution:\n", "# Atmospheric Pressure,\n", "Po=14.7; #psi \n", "# Absolute Pressure(Pa) =Gage Pressure + Atmospheric Pressure\n", "Pa=Pg+Po; #psi\n", "\n", "# Results:\n", "print \" Results: \"\n", "print \"The Absolute Pressure is psi.\",Pa\n" ] }, { "cell_type": "code", "execution_count": 15, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " Results: \n", "The specific weights is N/m**3. 8792\n", " The answer in the program is different than that in textbook. It may be due to no.s of significant digit in data and calculation\n" ] } ], "source": [ "##Example2_9\n", "# Aim:To Determine specific weights in N/m**3\n", "# Given:\n", "# specific weight:\n", "gamma1=56; #lb/ft**3\n", "\n", "\n", "# Solution:\n", "# We know,\n", "# 1 N/m**3 = 157 lb/ft**3\n", "gamma2=157*gamma1; #N/m**3\n", "\n", "# Results:\n", "print \" Results: \"\n", "print \"The specific weights is N/m**3.\",gamma2\n", "print \" The answer in the program is different than that in textbook. It may be due to no.s of significant digit in data and calculation\"\n", "\n" ] }, { "cell_type": "code", "execution_count": 16, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " Results: \n", " The temp at which Fahrenheit and Celsius values are equal is deg. -40.0\n" ] } ], "source": [ "##Example2_10\n", "# Aim:To find Temperature at which Fahrenheit and Celsius values are equal \n", "# Given:\n", "# T(degF) = T(degC) #Eqn - 1\n", "\n", "# Solution:\n", "# We know that,\n", "# T(degF)=((1.8*T(degC))+32) #Eqn - 2 \n", "# From Eqn 1 and 2\n", "# ((1.8*T(degC))+32)= T(degC)\n", "# (1-1.8)*T(degC)=32\n", "# -0.8*T(degC)=32\n", "TdegC=-32/0.8;\n", "\n", "# Results:\n", "print \" Results: \"\n", "print \" The temp at which Fahrenheit and Celsius values are equal is deg.\",TdegC\n" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.9" } }, "nbformat": 4, "nbformat_minor": 0 }