{
"metadata": {
"name": "",
"signature": "sha256:04b8728a2a112ab03efb0f888eacfe0c6847d92d7043fbf038fc0d7708b1bf9e"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter1-Introduction of Electronic Device"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg34"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.1\n",
"#calcualte fusing current for given values\n",
"import math\n",
"print(\"I = K(d^1.5)\") ##formula used for fusing current\n",
"d=0.0031\n",
"print\"%s %.3f %s\"%(\"d = \",d,\"inches\") ##initializing values of diameter\n",
"I1=10244*(d**1.5);\n",
"I2=7585*(d**1.5);\n",
"I3=5320*(d**1.5); \n",
"I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d^1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d^1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d^1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d^1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d^1.5) = \",I5,\"Amp.\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"I = K(d^1.5)\n",
"d = 0.003 inches\n",
"for Copper, I = 10244*(d^1.5) = 1.77 Amp.\n",
"for Aluminum, I = 7585*(d^1.5) = 1.31 Amp.\n",
"for Silver, I = 5320*(d^1.5) = 0.92 Amp.\n",
"for Iron, I = 3148*(d^1.5) = 0.54 Amp.\n",
"for Tin, I = 1642*(d^1.5) = 0.28 Amp.\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg34"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.2\n",
"#calculate fusing current for given values\n",
"print(\"fusing current, I = K(d**1.5) Amp.\")##formula used for fusing current\n",
"d=0.0201\n",
"print\"%s %.2f %s\"%(\"d = \",d,\"inches\") ##initializing value of diameter\n",
"I1=10244*(d**1.5);I2=7585*(d**1.5); I3=5320*(d**1.5); I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d**1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d**1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d**1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d**1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d**1.5) = \",I5,\"Amp.\")\n",
"\n",
"\n",
"## note : calculation for fusing current of Iron is wrong.\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"fusing current, I = K(d**1.5) Amp.\n",
"d = 0.02 inches\n",
"for Copper, I = 10244*(d**1.5) = 29.19 Amp.\n",
"for Aluminum, I = 7585*(d**1.5) = 21.61 Amp.\n",
"for Silver, I = 5320*(d**1.5) = 15.16 Amp.\n",
"for Iron, I = 3148*(d**1.5) = 8.97 Amp.\n",
"for Tin, I = 1642*(d**1.5) = 4.68 Amp.\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex3-pg35"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.3\n",
"#calculate for fusing current in all four cases\n",
"import math\n",
"print(\"fusing current, I = K(d**1.5) Amp.\") ##formula used for fusing current\n",
"print(\"(a)\") \n",
"d=0.0159\n",
"print\"%s %.2f %s\"%(\"d = \",d,\"inches\") ##initializing value of diameter\n",
"I1=10244*(d**1.5);I2=7585*(d**1.5); I3=5320*(d**1.5); I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d**1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d**1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d**1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d**1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d**1.5) = \",I5,\"Amp.\")\n",
"\n",
"\n",
"print(\"(b)\")\n",
"d=0.0063\n",
"print\"%s %.2f %s\"%(\"d = \",d,\"inches\") ##initializing value of diameter\n",
"I1=10244*(d**1.5);I2=7585*(d**1.5); I3=5320*(d**1.5); I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d**1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d**1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d**1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d**1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d**1.5) = \",I5,\"Amp.\")\n",
"\n",
"\n",
"print(\"(c)\")\n",
"d=0.0403\n",
"print\"%s %.2f %s\"%(\"d = \",d,\"inches\") ##initializing value of diameter\n",
"I1=10244*(d**1.5);I2=7585*(d**1.5); I3=5320*(d**1.5); I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d**1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d**1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d**1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d**1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d**1.5) = \",I5,\"Amp.\")\n",
"\n",
"\n",
"print(\"(d)\")\n",
"d=0.0452\n",
"print\"%s %.2f %s\"%(\"d = \",d,\"inches\") ##initializing value of diameter\n",
"I1=10244*(d**1.5);I2=7585*(d**1.5); I3=5320*(d**1.5); I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d**1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d**1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d**1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d**1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d**1.5) = \",I5,\"Amp.\")\n",
"\n",
"\n",
"print(\"(e)\")\n",
"d=0.0508\n",
"print\"%s %.2f %s\"%(\"d = \",d,\"inches\") ##initializing value of diameter\n",
"I1=10244*(d**1.5);I2=7585*(d**1.5); I3=5320*(d**1.5); I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d**1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d**1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d**1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d**1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d**1.5) = \",I5,\"Amp.\")\n",
"\n",
"\n",
"print(\"(f)\")\n",
"d=0.162\n",
"print\"%s %.2f %s\"%(\"d = \",d,\"inches\") ##initializing value of diameter\n",
"I1=10244*(d**1.5);I2=7585*(d**1.5); I3=5320*(d**1.5); I4=3148*(d**1.5); I5=1642*(d**1.5) ##calculation for fusing current\n",
"print\"%s %.2f %s\"%(\"for Copper, I = 10244*(d**1.5) = \",I1,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Aluminum, I = 7585*(d**1.5) = \",I2,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Silver, I = 5320*(d**1.5) = \",I3,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Iron, I = 3148*(d**1.5) = \",I4,\"Amp.\")\n",
"print\"%s %.2f %s\"%(\"for Tin, I = 1642*(d**1.5) = \",I5,\"Amp.\")\n",
"\n",
"\n",
"\n",
"## note : in part (e) ... calculation for fusing current of silver is wrong.\n",
"## note : in part (f) ... calculation for fusing current of Iron is wrong.\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"fusing current, I = K(d**1.5) Amp.\n",
"(a)\n",
"d = 0.02 inches\n",
"for Copper, I = 10244*(d**1.5) = 20.54 Amp.\n",
"for Aluminum, I = 7585*(d**1.5) = 15.21 Amp.\n",
"for Silver, I = 5320*(d**1.5) = 10.67 Amp.\n",
"for Iron, I = 3148*(d**1.5) = 6.31 Amp.\n",
"for Tin, I = 1642*(d**1.5) = 3.29 Amp.\n",
"(b)\n",
"d = 0.01 inches\n",
"for Copper, I = 10244*(d**1.5) = 5.12 Amp.\n",
"for Aluminum, I = 7585*(d**1.5) = 3.79 Amp.\n",
"for Silver, I = 5320*(d**1.5) = 2.66 Amp.\n",
"for Iron, I = 3148*(d**1.5) = 1.57 Amp.\n",
"for Tin, I = 1642*(d**1.5) = 0.82 Amp.\n",
"(c)\n",
"d = 0.04 inches\n",
"for Copper, I = 10244*(d**1.5) = 82.88 Amp.\n",
"for Aluminum, I = 7585*(d**1.5) = 61.36 Amp.\n",
"for Silver, I = 5320*(d**1.5) = 43.04 Amp.\n",
"for Iron, I = 3148*(d**1.5) = 25.47 Amp.\n",
"for Tin, I = 1642*(d**1.5) = 13.28 Amp.\n",
"(d)\n",
"d = 0.05 inches\n",
"for Copper, I = 10244*(d**1.5) = 98.44 Amp.\n",
"for Aluminum, I = 7585*(d**1.5) = 72.89 Amp.\n",
"for Silver, I = 5320*(d**1.5) = 51.12 Amp.\n",
"for Iron, I = 3148*(d**1.5) = 30.25 Amp.\n",
"for Tin, I = 1642*(d**1.5) = 15.78 Amp.\n",
"(e)\n",
"d = 0.05 inches\n",
"for Copper, I = 10244*(d**1.5) = 117.29 Amp.\n",
"for Aluminum, I = 7585*(d**1.5) = 86.85 Amp.\n",
"for Silver, I = 5320*(d**1.5) = 60.91 Amp.\n",
"for Iron, I = 3148*(d**1.5) = 36.04 Amp.\n",
"for Tin, I = 1642*(d**1.5) = 18.80 Amp.\n",
"(f)\n",
"d = 0.16 inches\n",
"for Copper, I = 10244*(d**1.5) = 667.95 Amp.\n",
"for Aluminum, I = 7585*(d**1.5) = 494.57 Amp.\n",
"for Silver, I = 5320*(d**1.5) = 346.88 Amp.\n",
"for Iron, I = 3148*(d**1.5) = 205.26 Amp.\n",
"for Tin, I = 1642*(d**1.5) = 107.06 Amp.\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex4-pg37"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.4\n",
"#calculate resistance for given resistivity\n",
"import math\n",
"A=0.5189*10**-6##wire cross sectional area\n",
"rho=1.725*10**-8##resistivity\n",
"l=100 ##wire length\n",
"print\"%s %.3e %s\"%(\"A =\",A,\"merer square\") \n",
"print\"%s %.2e %s\"%(\"rho =\",rho,\"ohm-m\")\n",
"print\"%s %.2f %s\"%(\"l =\",l,\"m\")\n",
"print\"%s %.2f %s\"%(\"R = rho*l/A = \",rho*l/A,\"ohm\") ##resistance\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"A = 5.189e-07 merer square\n",
"rho = 1.73e-08 ohm-m\n",
"l = 100.00 m\n",
"R = rho*l/A = 3.32 ohm\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex5-pg38"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.5\n",
"#calculate resistance wire\n",
"import math\n",
"A=0.2588*10**-6##wire cross-sectional area\n",
"rho=1.725*10**-8##resistivity\n",
"l=100 ##wire length\n",
"print\"%s %.2e %s\"%(\"A =\",A,\"merer square\")\n",
"print\"%s %.2e %s\"%(\"rho =\",rho,\"ohm-m\")\n",
"print\"%s %.2f %s\"%(\"l =\",l,\"m\")\n",
"print\"%s %.2f %s\"%(\"R = rho*l/A = \",rho*l/A,\"ohm\") ##resistance of wire\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"A = 2.59e-07 merer square\n",
"rho = 1.73e-08 ohm-m\n",
"l = 100.00 m\n",
"R = rho*l/A = 6.67 ohm\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex6-pg39"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.6\n",
"#calculate resistance at temperature at T2\n",
"R1 = 14##resistance at temperature T1 \n",
"alpha=0.005\n",
"T1=20;##initial temperature\n",
"T2=120 ##final temperature\n",
"print\"%s %.2f %s %.2f %s %.2f %s%.2f %s \"%(\"R1 = \",R1, \"ohm\"and\" alpha = \",alpha,\"\"and \" T1 = \",T1,\"degreeC\"and \"T2 = \",T2,\"degreeC\")\n",
"print\"%s %.2f %s\"%(\"R2 = R1(1+(alpha*(T1-T2))) = \",R1*(1+(alpha*(T2-T1))),\"ohm\") ##resistance at temperature T2\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"R1 = 14.00 alpha = 0.01 20.00 T2 = 120.00 degreeC \n",
"R2 = R1(1+(alpha*(T1-T2))) = 21.00 ohm\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex7-pg40"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##EX1.7\n",
"#calculate force of electron charge\n",
"import math\n",
"Ex=3;Ey=4;Ez=2##electric field\n",
"e=1.6*10**-19 ##electorn charge\n",
"print(\"E = 3ax + 4ay + 2az k V/m\")\n",
"print(\"e = 1.6*10**-19 C\")\n",
"print\"%s %.2e %s %.2e %s %.2e %s \"%(\" F=eE = \",Ex*e*1000,\"ax + \",Ey*e*1000,\"ay + \",Ez*e*1000,\"az N\") ##force\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"E = 3ax + 4ay + 2az k V/m\n",
"e = 1.6*10**-19 C\n",
" F=eE = 4.80e-16 ax + 6.40e-16 ay + 3.20e-16 az N \n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex8-pg40"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.8\n",
"#calculate elctric field\n",
"import math\n",
"F=0.1*10**-12##force applied\n",
"e = 1.6*10**-19##electron charge\n",
"print\"%s %.2e %s %.2e %s \"%(\"F= \",F,\"N \"and \" e = \",e,\"C\")\n",
"print\"%s %.2f %s\"%(\"E = F/e =\",F/e,\"V/m\")##electric field\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"F= 1.00e-13 e = 1.60e-19 C \n",
"E = F/e = 625000.00 V/m\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex9-pg41"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.9\n",
"#calculate charge of electron\n",
"import math\n",
"F = 3*(10**-12) ##force applied\n",
"E = 5*(10**-6) ##electric field\n",
"print\"%s %.2e %s\"%(\"F = \",F,\"N\")\n",
"print\"%s %.2e %s\"%(\"E = \",E,\"V/m\")\n",
"print\"%s %.2e %s\"%(\"Q= F/E = \",F/E,\"C\") ##chage\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"F = 3.00e-12 N\n",
"E = 5.00e-06 V/m\n",
"Q= F/E = 6.00e-07 C\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10-pg44"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.10\n",
"#calculate force \n",
"import math\n",
"B = 2*10**-6 ##magnetic flux density\n",
"V = 4*10**6 ##electron velocity\n",
"e= 1.6*10**-19##elcetron charge\n",
"print\"%s %.2e %s\"%(\"B =\",B,\"ax wb/m.sq\")\n",
"print\"%s %.2f %s\"%(\"V =\",V,\"az m/s\")\n",
"print\"%s %.3e %s\"%(\"e = \",e, \"C\")\n",
"print\"%s %.2e %s\"%(\"F = e[VxB] =\",e*V*B,\"ay N\")##force\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"B = 2.00e-06 ax wb/m.sq\n",
"V = 4000000.00 az m/s\n",
"e = 1.600e-19 C\n",
"F = e[VxB] = 1.28e-18 ay N\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Ex11-pg44"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex1.11\n",
"#calculate force on electron due to field\n",
"import math\n",
"Hx = 1*10**-3 ##magnetic field in x-axis\n",
"Hy = 2*10**-3 ##magnetic field in y-axis\n",
"V = (4*10**6) ##electron velocity\n",
"micro_not=(4*math.pi*(10**-7)) ##permitivity in vaccum\n",
"e=1.6*10**-19 ##charge of electorn\n",
"print\"%s %.2e %s %.2e %s \"%(\" H = \",Hx,\"ax + \",Hy,\"ay A/m\")\n",
"print\"%s %.2f %s\"%(\"V = \",V,\"ay m/s\")\n",
"Bx = micro_not*Hx; By = micro_not*Hy ##magnetic flux density\n",
"print\"%s %.2e %s %.2e %s \"%(\"B = micro_not*H = \",Bx,\"ax + \",By,\"ay wb/m.sq\")\n",
"print\"%s %.2e %s \"%(\"F = e[VxB] = \",e*V*Bx,\"az N\") ##force on electron due to field\n",
"\n",
"\n",
"## note : there is a misprint in the textbook for the above problem\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" H = 1.00e-03 ax + 2.00e-03 ay A/m \n",
"V = 4000000.00 ay m/s\n",
"B = micro_not*H = 1.26e-09 ax + 2.51e-09 ay wb/m.sq \n",
"F = e[VxB] = 8.04e-22 az N \n"
]
}
],
"prompt_number": 11
}
],
"metadata": {}
}
]
}