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  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter2-Nuclear Engineering"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Ex1-pg54"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "## Example 2.1\n",
      "import math\n",
      "#determine atoms in deuterium\n",
      "## Given data\n",
      "atom_h = 6.6*10**24;                      ## Number of atoms in Hydrogen\n",
      "## Using the data given in Table II.2, Appendix II for isotropic abundance of deuterium\n",
      "isoab_H2 = 0.015;                        ## Isotropic abundance of deuterium\n",
      "## Calculation\n",
      "totatom_d=(isoab_H2*atom_h)/100.;\n",
      "## Result\n",
      "print\"%s %.2e %s \"%('\\n Number of deuterium atoms = ',totatom_d,'');\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        " Number of deuterium atoms =  9.90e+20  \n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Ex2-pg54"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "## Example 2.2\n",
      "import math\n",
      "#determine atomic weight of oxygen\n",
      "## Given data \n",
      "## Using the data given in the example 2.2\n",
      "atwt_O16 = 15.99492;                      ## Atomic weight of O-16 isotope\n",
      "isoab_O16 = 99.759;                       ## Abundance of O-16 isotope\n",
      "atwt_O17 = 16.99913;                      ## Atomic weight of O-17 isotope\n",
      "isoab_O17 = 0.037;                        ## Abundance of O-17 isotope\n",
      "atwt_O18 = 17.99916;                      ## Atomic weight of O-18 isotope\n",
      "isoab_O18 = 0.204;                        ## Abundance of O-18 isotope\n",
      "## Calculation\n",
      "atwt_O=(isoab_O16*atwt_O16 + isoab_O17*atwt_O17 + isoab_O18*atwt_O18)/100.;\n",
      "## Result\n",
      "print\"%s %.2f %s \"%('\\n Atomic Weight of Oxygen = ',atwt_O,'');\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        " Atomic Weight of Oxygen =  16.00  \n"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Ex3-pg55"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "## Example 2.3\n",
      "import math\n",
      "#determine rest mass energy of electron\n",
      "## Given data\n",
      "me = 9.1095*10**(-28);                     ## Mass of electron in grams\n",
      "c = 2.9979*10**10;                         ## Speed of light in vacuum in cm/sec\n",
      "## Calculation\n",
      "rest_mass = me*c**2;\n",
      "## Result\n",
      "print\"%s %.2e %s \"%('\\n Rest mass energy of electron = ',rest_mass,' ergs\\n');\n",
      "print('Expressing the result in joules')\n",
      "## 1 Joule = 10^(-7)ergs\n",
      "rest_mass_j = rest_mass*10**(-7);\n",
      "print\"%s %.2e %s \"%('\\n Rest mass energy of electron = ',rest_mass_j,' joules\\n');\n",
      "print('Expressing the result in MeV')\n",
      "## 1 MeV = 1.6022*10^(-13)joules\n",
      "rest_mass_mev = rest_mass_j/(1.6022*10**(-13));\n",
      "print\"%s %.2f %s \"%('\\n Rest mass energy of electron = ',rest_mass_mev,' MeV\\n');\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        " Rest mass energy of electron =  8.19e-07  ergs\n",
        " \n",
        "Expressing the result in joules\n",
        "\n",
        " Rest mass energy of electron =  8.19e-14  joules\n",
        " \n",
        "Expressing the result in MeV\n",
        "\n",
        " Rest mass energy of electron =  0.51  MeV\n",
        " \n"
       ]
      }
     ],
     "prompt_number": 4
    }
   ],
   "metadata": {}
  }
 ]
}