{
"metadata": {
"name": "",
"signature": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 01 : Standards, Units & Dimensions"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.17 : page 56"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"Y=90.0 \n",
"X=89.0 \n",
"Error_absolute=Y-X \n",
"print 'absolute Error =',Error_absolute\n",
"Error_relative=(Y-X)*100/Y \n",
"print 'relative Error =',round(Error_relative,2),'%'\n",
"Accuracy_relative=1-Error_relative \n",
"print 'Accuracy relative =',round(Accuracy_relative,2)\n",
"Accuracy_percentage=100*Accuracy_relative \n",
"print 'Accuracy =',round(Accuracy_percentage,2),'%'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"absolute Error = 1.0\n",
"relative Error = 1.11 %\n",
"Accuracy relative = -0.11\n",
"Accuracy = -11.11 %\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.18 : page "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"S=98+100+102+98+100+100+104+104+105+97 \n",
"n=10 \n",
"Avg=S/n \n",
"P=1-abs((104-Avg)/Avg) \n",
"print \"Precision for the 8th reading=%.2f\"%P"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Precision for the 8th reading=0.97\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.19 : page "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"V=10 \n",
"I=20*10**-3 \n",
"RI=50 \n",
"R=(V/I)-RI \n",
"print \"The value of Resistance = %.0f ohm\"%R \n",
"dV=0.2 \n",
"dI=1*10**-3 \n",
"dRI=5 \n",
"dR=(dV/I)+(V*dI/I**2)+(dRI)\n",
"print \"Limiting error of resistance = %.0f ohm\"%dR"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Resistance = 450 ohm\n",
"Limiting error of resistance = 40 ohm\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.20 : page "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"R0=5 \n",
"a=0.004 \n",
"T=30 \n",
"R=R0*(1+a*(T-20)) \n",
"print \"Resistance of the wire = %.1f ohm\"%R \n",
"#Let (dR/dR0) =b (dR/da)=c (dR/dT)=d\n",
"b=(1+a*(T-20)) \n",
"c=R0*(T-20) \n",
"d=R0*a \n",
"ur0=5*0.003 \n",
"ua=0.004*0.01 \n",
"ut=1 \n",
"uR=(b**2*ur0**2+c**2*ua**2+d**2*ut**2)**0.5 \n",
"print \"Uncertanity in resistance = %.2f ohm\"%uR"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistance of the wire = 5.2 ohm\n",
"Uncertanity in resistance = 0.03 ohm\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.21 : page "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"X_mean=(15+20+25+30+35+45)/6 \n",
"print \"The sample mean of the temperature=%.2f degree C\"%X_mean \n",
"Y_mean=(1.9+1.93+1.97+2+2.01+2.01+1.94+1.95+1.97+2.02+2.02+2.04)/12*10**-6 \n",
"print \"The sample mean of the faliure=%.6f failures/hour\"%Y_mean\n",
"print 'from these values we get' \n",
"a=1.80*10**-6 \n",
"b=0.00226 \n",
"print 'Y=1.80+0.00226x is the required least square line'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The sample mean of the temperature=28.33 degree C\n",
"The sample mean of the faliure=0.000002 failures/hour\n",
"from these values we get\n",
"Y=1.80+0.00226x is the required least square line\n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.22 : page "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"n=2 \n",
"k=1 \n",
"dof=n-k \n",
"chi_square=(3-5)**2/5+(7-5)**2/5 \n",
"print 'Chi square value =',chi_square\n",
"print 'From the dof and chi square value we find P=0.22'\n",
"print 'Hence there are 22% chance that the distribution is just the result of random fluctuations and the coin may be unweighted'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Chi square value = 1.6\n",
"From the dof and chi square value we find P=0.22\n",
"Hence there are 22% chance that the distribution is just the result of random fluctuations and the coin may be unweighted\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.23 : page "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"X_mean=501*1/5 \n",
"print \"Assigned Value=%.1f V\"%X_mean \n",
"sigma=((1/(5-1))*((100.2-X_mean)**2+(100.3-X_mean)**2+(100.2-X_mean)**2+(100.2-X_mean)**2+(100.1-X_mean)**2))**0.5 \n",
"# For 95% confidance level student factor t is 2.78'\n",
"t=2.78 \n",
"n=5 \n",
"Ur=t*sigma/(n**0.5) \n",
"print \"Uncertanity=%.3f V\"%Ur "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Assigned Value=100.2 V\n",
"Uncertanity=0.088 V\n"
]
}
],
"prompt_number": 23
}
],
"metadata": {}
}
]
}