{ "metadata": { "name": "", "signature": "sha256:0634d7bf5367e0141c25c22bd055ab7dd0d67262eacfb1ab474c7c9ba196985e" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 1 Qualities of measurments" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.1 Page no 3" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "V=80.0 #expected value of voltage in Volts\n", "V1=79 #Volts\n", "\n", "#Calculation\n", "E=V-V1\n", "E1=((V-V1)/V)*100\n", "E2=1-((V-V1)/V)\n", "A=100*E2\n", "#Result\n", "print\"(i) Absolute error is \",E,\"V\"\n", "print\"(ii) percent error is \", E1,\"%\"\n", "print\"(iii) reletive error is \", E2\n", "print\"(iv) percent of accuracy is \", A,\"%\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(i) Absolute error is 1.0 V\n", "(ii) percent error is 1.25 %\n", "(iii) reletive error is 0.9875\n", "(iv) percent of accuracy is 98.75 %\n" ] } ], "prompt_number": 14 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.2 Page no 4" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "x1=98\n", "x2=101\n", "x3=102\n", "x4=97\n", "x5=101\n", "x6=100\n", "x7=103\n", "x8=98\n", "x9=106\n", "x10=99\n", "\n", "#Calculation\n", "X=(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10.0\n", "P=(x6/X)\n", "\n", "#Result\n", "print\"Precision of the 6th measurment is \",round(P,3)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Precision of the 6th measurment is 0.995\n" ] } ], "prompt_number": 26 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.3(a) Page no 7" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#given\n", "V=80 #milliammeter readings\n", "I=10.0 #mA\n", "V1=150 #Volts\n", "R1=1000 #ohm/volt\n", "\n", "#Calculation\n", "R=V/I\n", "Rv=R1*V1\n", "Rx=(R*V1)/(V1-R)\n", "E=((Rx-R)/Rx)*100\n", "\n", "#Result\n", "print\"(i) Apparent resistance of the unknown resistance \",R,\"K ohm\"\n", "print \"Actual resistance of the unknown resistance is \",round(Rx,2),\"K ohm\"\n", "print \"Error due to the loading effet of the voltmeter \",round(E,1),\"%\" " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(i) Apparent resistance of the unknown resistance 8.0 K ohm\n", "Actual resistance of the unknown resistance is 8.45 K ohm\n", "Error due to the loading effet of the voltmeter 5.3 %\n" ] } ], "prompt_number": 104 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.3(b) Page no 7" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "V=30 #Volts\n", "V1=150 #Volts\n", "I=0.6 #A\n", "R1=1000 #ohm/volts\n", "\n", "#Calculation\n", "R=V/I\n", "Rv=(R1*V1)\n", "Rx=(R*Rv)/(Rv-R)\n", "E=((Rx-R)/Rx)*100\n", "\n", "#Result\n", "print\"(i) total circuit resistance is \", R,\"ohm\"\n", "print \"(ii) The voltmeter resistance is \",round(Rx,2)\n", "print\"(iii) Error due to loading effect of voltmeter \", round(E,3),\"%\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(i) total circuit resistance is 50.0 ohm\n", "(ii) The voltmeter resistance is 50.02\n", "(iii) Error due to loading effect of voltmeter 0.033 %\n" ] } ], "prompt_number": 113 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.4 Page no 12" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "x1=49.7\n", "x2=50.1\n", "x3=50.2\n", "x4=49.6\n", "x5=49.7\n", "\n", "#Calculation\n", "X=(x1+x2+x3+x4+x5)/5.0\n", "d1=x1-X\n", "d2=x2-X\n", "d3=x3-X\n", "d4=x4-X\n", "d5=x5-X\n", "dtotal=(d1+d2+d3+d4+d5)\n", "\n", "#Result\n", "print\"(i) Arithmetic mean is \", X\n", "print\"(ii) derivations from each value are\"\n", "print \"d1=\",d1,\"\\nd2=\",d2,\"\\nd3=\",d3,\"\\nd4=\",d4,\"\\nd5=\",d5\n", "print\"(iii) The algebric sum of derivative is \",round(dtotal,2)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(i) Arithmetic mean is 49.86\n", "(ii) derivations from each value are\n", "d1= -0.16 \n", "d2= 0.24 \n", "d3= 0.34 \n", "d4= -0.26 \n", "d5= -0.16\n", "(iii) The algebric sum of derivative is 0.0\n" ] } ], "prompt_number": 77 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.5 Page no 14" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "x1=49.7\n", "x2=50.1\n", "x3=50.2\n", "x4=49.6\n", "x5=49.7\n", "\n", "#Calculation\n", "X=(x1+x2+x3+x4+x5)/5.0\n", "d1=x1-X\n", "d2=x2-X\n", "d3=x3-X\n", "d4=x4-X\n", "d5=x5-X\n", "dtotal=(d1+d2+d3+d4+d5)/5.0\n", "\n", "#Result\n", "print\"The average deviation is \",round(dtotal*10**14,3)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The average deviation is 0.284\n" ] } ], "prompt_number": 86 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.6 Page no 14" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "d1= -0.16 \n", "d2= 0.24 \n", "d3= 0.34 \n", "d4= -0.26 \n", "d5= -0.16\n", "\n", "#Calculation\n", "import math\n", "D=math.sqrt((d1**2+d2**2+d3**2+d4**2+d5**2)/4.0)\n", "print\"The standard deviation is \",round(D,2)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The standard deviation is 0.27\n" ] } ], "prompt_number": 90 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.7 Page no 15" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "V=600 #Volts\n", "V1=250.0 #Volts\n", "a=0.02\n", "\n", "#Calculation\n", "M=a*V\n", "E=(M/V1)*100\n", "\n", "#Result\n", "print\"The limited error is \", E,\"%\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The limited error is 4.8 %\n" ] } ], "prompt_number": 94 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.8 Page no 15" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "V=70.0 #Volts\n", "V1=100 #Volts\n", "I=80.0 #mA\n", "I1=150 #mA\n", "a=0.015\n", "\n", "#calculation\n", "M=a*V1\n", "E=(M/V)*100\n", "E1=a*I1\n", "E2=(E1/I)*100\n", "E3=E+E2\n", "\n", "#Result\n", "print\"limiting error is \",round (E3,3),\"%\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "limiting error is 4.955 %\n" ] } ], "prompt_number": 102 } ], "metadata": {} } ] }