{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "

Chapter No 7 : Field Effect Transistor

" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.1, Page No 323" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variables\n", "I_DSS = 15.0 #in mA\n", "V_GS_off = -5.0 #in V\n", "V_GS = 0 #in V\n", "\n", "#CALCULATIONS\n", "I_D = I_DSS*((1-(V_GS/V_GS_off))**2) #in mA\n", "V_GS = -1 #in V\n", "I_D1 = I_DSS*((1.0-(V_GS/V_GS_off))**2) #in mA\n", "V_GS = -4 #in V\n", "I_D2 = I_DSS*((1-(V_GS/V_GS_off))**2) #in mA\n", "\n", "#RESULTS\n", "print('When V_GS=0, the drain current is =%.f mA ' %I_D)\n", "print('When V_GS=-1V, the drain current is =%.2f mA ' %I_D1)\n", "print('The interplanner spacing is =%.2f \u00c5' %I_D2)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "When V_GS=0, the drain current is =15 mA \n", "When V_GS=-1V, the drain current is =9.60 mA \n", "The interplanner spacing is =0.60 \u00c5\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.4, Page No 327" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "I_DSS = 20.0 #in mA\n", "V_P = -8 #in V\n", "g_mo = 5000.0 #in \u00b5s\n", "V_GS = -4.0 #in V\n", "\n", "#CALCULATIONS\n", "\n", "I_D = I_DSS*((1-(V_GS/V_P))**2) #in mA\n", "g_m = g_mo*(1-(V_GS/V_P)) #in \u00b5s\n", "\n", "#RESULTS\n", "print('The value of drain current is =%.f mA ' %I_D)\n", "print('The transconductance is =%.f \u00b5s' %g_m)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of drain current is =5 mA \n", "The transconductance is =2500 \u00b5s\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.5 Page No 327" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "\n", "\n", "#initialisation of variables\n", "I_D1 = 10.0 #in mA\n", "V_GS = -12.0 #in V\n", "V_GSth = -3.0 #in V\n", "\n", "#CALCULATIONS\n", "K = I_D1/( (V_GS-V_GSth)**2 ) #in mA/V\n", "V_GS= -6 #in V\n", "I_D = K*((V_GS-V_GSth)**2) #in mA\n", "\n", "#RESULTS\n", "print('The value of I_D is =%.2f mA ' %I_D)\n", "print('Approximation error')" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of I_D is =1.11 mA \n", "Approximation error\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.7, Page No 327" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "V_GS = -2.0 #in V\n", "V_P = -5.0 #in V\n", "V_DS = V_GS-V_P #in V\n", "I_DSS = 8.0 #in mA\n", "\n", "#CALCULATIONS\n", "I_D = I_DSS*((1-(V_GS/V_P))**2) #in mA\n", "\n", "#RESULTS\n", "print('The minimum value of V_DS is =%.f V ' %V_DS)\n", "print('The drain current is =%.2f mA' %I_D)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The minimum value of V_DS is =3 V \n", "The drain current is =2.88 mA\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.8 Page No 328" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "V_P = -2 #in V\n", "I_DSS = 1.65 #in mA\n", "I_D = 0.8 #in mA\n", "V_DD = 24.0 #in V\n", "\n", "#CALCULATIONS\n", "V_GS = V_P*(1- math.sqrt(I_D/I_DSS) ) #in V\n", "g_mo = -(2*I_DSS)/V_P #in mS\n", "g_m = g_mo*(1-(V_GS/V_P)) #in mS\n", "\n", "#RESULTS\n", "print('The value of V_GS is =%.2f V ' %V_GS)\n", "print('The value of g_m is =%.2f mS' %g_m)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of V_GS is =-0.61 V \n", "The value of g_m is =1.15 mS\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.9 Page No 328" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "V_P = 5.0 #in V\n", "I_DSS = -40.0 #in mA\n", "I_D = -15.0 #in mA\n", "\n", "#CALCULATIONS\n", "V_GS = V_P*(math.sqrt(I_D/I_DSS)-1 ) #in V\n", "\n", "#RESULTS\n", "print('The gate source voltage is =%.2f V' %(V_GS*-1))\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The gate source voltage is =1.94 V\n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.10, Page No 328" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "I_D1 = 1.9 #in mA\n", "I_D2 = 1.0 #in mA\n", "\n", "#CALCULATIONS\n", "del_I_D = I_D1-I_D2 #in mA\n", "V_GS2 = -3.3 #in V\n", "V_GS1 = -3.0 #in V\n", "del_V_GS = V_GS1-V_GS2 #in V\n", "g_m = del_I_D/del_V_GS #in mA/V\n", "g_m = g_m * 10**3 #in \u00b5 mhos\n", "\n", "#RESULTS\n", "print('The value of transconductance is =%.f \u00b5 mhos ' %g_m)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of transconductance is =3000 \u00b5 mhos \n" ] } ], "prompt_number": 8 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.11 Page No 329" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math \n", "\n", "#initialisation of variables\n", "V_DS1 = 14.0 #in V\n", "V_DS2 = 5.0 #in V\n", "del_V_DS = V_DS1-V_DS2 # in V\n", "I_D1 = 3.3 #in mA\n", "I_D2 = 3 # in mA\n", "\n", "#CALCULATIONS\n", "del_I_D = I_D1-I_D2 #in mA\n", "r_d = del_V_DS/del_I_D #in k ohms\n", "print('The drain resistance is =%.f k ohms' %r_d)\n", "V_GS1 = 0.4 #in V\n", "V_GS2 = 0.1 #in V\n", "del_V_GS = V_GS1-V_GS2 #in V\n", "I_D1 = 3.3 #in mA\n", "I_D2 = 0.71 #in mA\n", "del_I_D = I_D1-I_D2 # in mA\n", "g_m = del_I_D/del_V_GS # in mA/V\n", "g_m = g_m * 10**3 # in \u00b5mhos\n", "\n", "\n", "#RESULTS\n", "print('The transconductance is =%.f \u00b5mhos ' %g_m)\n", "Miu =r_d*10**3*g_m*10**-6\n", "print('Amplification factor is =%.f ' %Miu)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The drain resistance is =30 k ohms\n", "The transconductance is =8633 \u00b5mhos \n", "Amplification factor is =259 \n" ] } ], "prompt_number": 9 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.12 Page No 334" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "q = 1.6*10**-19 #in C\n", "N_D = 10**15*10**6 #electrons/m^3\n", "a = 3*10**-4 #in cm\n", "a=a*10**-2 #in m\n", "\n", "#CALCULATIONS\n", "Epsilon_o = (36 * math.pi * 10**9)**-1\n", "Epsilon = 12*Epsilon_o\n", "V_P = (q*N_D*((a)**2))/(2*Epsilon) #in V\n", "print('Pinch off voltage is =%.2f V ' %V_P)\n", "V_GS = 1.0 #in V\n", "V_P = 2.0 #in V\n", "b = a*( 1-math.sqrt(V_GS/V_P) ) #in m\n", "b = b * 10**6 #in \u00b5m\n", "\n", "#RESULTS\n", "print('The channel half width is =%.2f \u00b5m' %b)\n", "# Note: In the book, the unit of channel half width is wrong." ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Pinch off voltage is =6.79 V \n", "The channel half width is =0.88 \u00b5m\n" ] } ], "prompt_number": 10 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7.13 Page No 335" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "I_DSS = 8.0 #in mA\n", "V_P = -4.0 #in V\n", "a = 3*10**-4 #in cm\n", "N_D = 10**15 #in electrons/cm^3\n", "I_D = 3.0 #in mA\n", "\n", "#CALCULATIONS\n", "V_GS = V_P*( 1-math.sqrt(I_D/I_DSS) ) #in V\n", "V_DS_sat = V_GS-V_P #in V\n", "\n", "\n", "#RESULTS\n", "print('The value of V_GS is =%.2f V' %V_GS)\n", "print('The value of V_DS_sat is =%.2f V ' %V_DS_sat)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of V_GS is =-1.55 V\n", "The value of V_DS_sat is =2.45 V \n" ] } ], "prompt_number": 11 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example No 7.14 Page No 335" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variables\n", "V_P = -4 #in V\n", "I_DSS = 9.0 #in mA\n", "V_GS = -2.0 #in V\n", "\n", "#CALCULATIONS\n", "I_D = I_DSS*(( 1-(V_GS/V_P) )**2) #in mA\n", "\n", "#RESULTS\n", "print('The drain current is =%.2f mA ' %I_D)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The drain current is =2.25 mA \n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example No 7.15 Page No 335" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variables\n", "I_DSS = 12.0 #in mA\n", "V_P = -6.0 #in V\n", "V_GS = -1.0 #in V\n", "\n", "#CALCULATIONS\n", "g_mo = (-2*I_DSS)/V_P #in mA/V\n", "g_m = g_mo*(1-(V_GS/V_P)) #in mS\n", "\n", "#RESULTS\n", "print('The value of transconductance is =%.2f mS' %g_m)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of transconductance is =3.33 mS\n" ] } ], "prompt_number": 13 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example No 7.16 Page No 336" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variables\n", "I_DSS = 10.0 #in mA\n", "V_P = -5.0 #in V\n", "V_GS = -2.5 #in V\n", "\n", "#CALCULATIONS\n", "g_m = ((-2*I_DSS)/V_P)*(1-(V_GS/V_P)) #in mS .... correction\n", "I_D = I_DSS * ((1-(V_GS/V_P))**2) #in mA\n", "\n", "\n", "#RESULTS\n", "print('The transconductance is =%.f mS ' %g_m)\n", "print('The drain current is =%.2f mA ' %I_D)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The transconductance is =2 mS \n", "The drain current is =2.50 mA \n" ] } ], "prompt_number": 14 } ], "metadata": {} } ] }