{ "metadata": { "name": "", "signature": "sha256:41187fe2c381fd7b42e97b2fb4a9a8ffca57cedad7f414bab15784b2fa882a72" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter2:ELECTROMAGNETIC PLANE WAVES" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex2.6.5:pg-69" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", " \n", "import math \n", "#(a) Program to find gold-film surface resistance \n", " \n", " \n", "t=80*(10**(-10)) #Film Thickness\n", "o=4.1*(10**7) #Bulk conductivity \n", "p=570*(10**(-10)) #Electron mean free path \n", "of=((3*t*o)/(4*p))*(0.4228 + math.log(p/t)) #the gold-film conductivity is of=(3*t*o/4*p)*(0.4228 + ln(p/t)) \n", "\n", "Rs=1/(t*of) #the gold-film surface resistance is given by Rs=1/(t*of) in Ohms per square\n", "\n", "\n", "print\"The gold film surface resistance in Ohms per square is=\",round(Rs,2),\"Ohms/square\"\n", "\n", "\n", "#(b) Program to find the microwave attenuation \n", "\n", "Attenuation=40-20*log10(Rs) #Microwave attenuation \n", "\n", "print\"Microwave Attenuation in db is=\",int(Attenuation),\"db\"\n", "\n", "\n", "#(c)Light transmittance T\n", "\n", "print\"From figure No.2-6-5 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for gold film, we find that for given gold film of thickness 80 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 75%\"\n", "\n", "\n", "#(d)light reflection loss R\n", "\n", "print\"From the same figure the LIGHT REFLECTION LOSS R is about 25%\"\n", " " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The gold film surface resistance in Ohms per square is= 12.14 Ohms/square\n", "Microwave Attenuation in db is= 18 db\n", "From figure No.2-6-5 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for gold film, we find that for given gold film of thickness 80 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 75%\n", "From the same figure the LIGHT REFLECTION LOSS R is about 25%\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex2.6.6:pg-74" ] }, { "cell_type": "code", "collapsed": false, "input": [ " \n", "import math \n", "#(a) Program to find copper-film surface resistance \n", " \n", " \n", "t=60*(10**(-10)) #Film Thickness\n", "o=5.8*(10**7) #Bulk conductivity \n", "p=420*(10**(-10)) #Electron mean free path \n", "of=((3*t*o)/(4*p))*(0.4228 + math.log(p/t)) #the copper-film conductivity is of=(3*t*o/4*p)*(0.4228 + ln(p/t))\n", "Rs=1/(t*of) #the copper-film surface resistance is given by Rs=1/(t*of) in Ohms per square\n", "\n", "print\"The copper-film surface resistance in Ohms per square is=\",round(Rs,2),\"Ohms/square\"\n", "\n", "\n", "#(b) Program to find the microwave attenuation \n", "\n", "Attenuation=40-20*log10(Rs) #Microwave attenuation \n", "\n", "print\"Microwave Attenuation in db is=\",int(round(Attenuation)),\"db\"\n", "\n", "#(c)Light transmittance T\n", "\n", "print\"From figure No.2-6-11 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for copper film, we find that for given copper film of thickness 60 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 82%\"\n", "\n", "#(d)light reflection loss R\n", "\n", "print\"From the same figure the LIGHT REFLECTION LOSS R is about 18%\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The copper-film surface resistance in Ohms per square is= 11.32 Ohms/square\n", "Microwave Attenuation in db is= 19 db\n", "From figure No.2-6-11 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for copper film, we find that for given copper film of thickness 60 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 82%\n", "From the same figure the LIGHT REFLECTION LOSS R is about 18%\n" ] } ], "prompt_number": 2 }, { "cell_type": "code", "collapsed": false, "input": [], "language": "python", "metadata": {}, "outputs": [] } ], "metadata": {} } ] }