{
"metadata": {
"name": "",
"signature": "sha256:52e9ff37336a0b3392520c7ec0e817b37056adea4740de3297c85e4e3e83dc56"
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"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 33 Solids"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 33.1 Page no 904"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"Eg=0.72*1.6*10**-19 #J\n",
"h=6.62*10**-34\n",
"c=3*10**8\n",
"\n",
"#Calculation\n",
"L=(h*c)/Eg\n",
"\n",
"#Result\n",
"print\"The maximum wavelength of electromagnetic radiation is\",round(L*10**6,3)*10**-6,\"m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The maximum wavelength of electromagnetic radiation is 1.724e-06 m\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 33.2 Page no 904"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"n1=1.5*10**16 #/m**3\n",
"nh=4.5*10**22\n",
"\n",
"#Calculation\n",
"ne=n1**2/nh\n",
"\n",
"#Result\n",
"print\"ne in the doping silicon is\",ne*10**-9,\"*10**9 /m**3\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"ne in the doping silicon is 5.0 *10**9 /m**3\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 33.3 Page no 904"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"ne=8*10**19 #/m**3\n",
"nh=5*10**18\n",
"ue=2.3 #m**2/V/S\n",
"uh=0.01\n",
"e=1.6*10**-19\n",
"\n",
"#Calculation\n",
"a=1/(e*((ne*ue)+(nh*uh)))\n",
"\n",
"#Result\n",
"print\"(a) The semiconductor has greater electron concentration, it is n-type semiconductor\"\n",
"print\"(b) Resistivity is\", round(a*10**2,3),\"*10**-2 ohm/m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a) The semiconductor has greater electron concentration, it is n-type semiconductor\n",
"(b) Resistivity is 3.396 *10**-2 ohm/m\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 33.4 Page no 904"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"e=1.6*10**-19 #C\n",
"A=500 #ohm**-1 m**-1\n",
"Ue=0.39 #m**2 V**-1 s**-1\n",
"\n",
"#Calculation\n",
"Ne=A/(e*Ue)\n",
"\n",
"#Result\n",
"print\"The number density of donor atoms is\",round(Ne*10**-21,3)*10**21,\"m**3\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The number density of donor atoms is 8.013e+21 m**3\n"
]
}
],
"prompt_number": 23
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 33.5 Page no 904"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"F=1.6*10**-19 #E\n",
"W=4.2*10**8\n",
"e=2.4\n",
"w=4.2*10**-8\n",
"\n",
"#Calculation\n",
"S=F*W\n",
"A=S/F\n",
"E=e/w\n",
"\n",
"#Result\n",
"print\"Electric field is\", round(E*10**-7,2),\"*10**7 V/m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Electric field is 5.71 *10**7 V/m\n"
]
}
],
"prompt_number": 30
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 33.6 Page no 904"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"h=6.62*10**-34\n",
"c=3*10**8\n",
"l=630*10**-9\n",
"e=1.6*10**-19\n",
"\n",
"#Calculation\n",
"Eg=(h*c)/(l*e)\n",
"\n",
"#Result\n",
"print\"Width of the forbidden energy gap is\",round(Eg,2),\"eV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Width of the forbidden energy gap is 1.97 eV\n"
]
}
],
"prompt_number": 33
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 33.7 Page no 904"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#iven\n",
"A=10**-4 #m**2\n",
"l=0.1 #m\n",
"V=2 #V\n",
"T=300 #K\n",
"ue=0.135 #m**2/V/S\n",
"n=1.5*10**15 #/m**3\n",
"uh=0.048 #m**2/V/S\n",
"e=1.6*10**-19\n",
"ue1=0.39\n",
"uh1=0.19\n",
"n1=2.4*10**19\n",
"\n",
"#Calculation\n",
"E=V/l\n",
"ve=ue*E\n",
"vh=uh*E\n",
"Ie=e*A*n*ve\n",
"Ih=e*A*n*vh\n",
"I=Ie+Ih\n",
"ve1=ue1*E\n",
"ve2=uh1*E\n",
"Ie1=e*A*n1*ve1\n",
"Ie2=e*A*n1*ve2\n",
"I1=Ie1+Ie2\n",
"\n",
"#Result\n",
"print\"Electron current is\", Ie*10.0,\"A \\nHole current is\",Ih*10,\"A\"\n",
"print\"Magnitude of total current is\",I*10,\"A \\nTotal current when germanium is used is\",I1*10**3,\"*10**-3 A\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Electron current is 6.48e-07 A \n",
"Hole current is 2.304e-07 A\n",
"Magnitude of total current is 8.784e-07 A \n",
"Total current when germanium is used is 4.4544 *10**-3 A\n"
]
}
],
"prompt_number": 48
}
],
"metadata": {}
}
]
}