{
"metadata": {
"name": "",
"signature": "sha256:487f66e71ac79d9579f4a8e998f21bc6fadb0986ba14ee5d89b77699b48cadee"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 28 Particle nature of radiation"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.1 Page no 801"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"l=4950.0*10**-10\n",
"h=6.6*10**-34 #js\n",
"c=3*10**8 #m/s\n",
"\n",
"#Calculation\n",
"E=(h*c/l)/(1.6*10**-19)\n",
"\n",
"#Result\n",
"print\"Energy of each photon is\",E,\"eV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Energy of each photon is 2.5 eV\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.2 Page no 801"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"E=6.62 #J\n",
"v=10**12 #Hz\n",
"h=6.62*10**-34\n",
"\n",
"#Calculation\n",
"E1=h*v\n",
"n=E/(h*v)\n",
"\n",
"#Result\n",
"print\"Number of photons is\",n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Number of photons is 1e+22\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.3 Page no 801"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"h=6.62*10**-34 #js\n",
"c=3*10**8 #m/s\n",
"Iev=1.6*10**-19 #J\n",
"V=10**6 #hz\n",
"V1=5890*10**-10 #m\n",
"L=10.0**-10 #m\n",
"\n",
"#Calculation\n",
"E=h*v\n",
"E1=E/Iev\n",
"A=(h*c)/V1\n",
"A1=A/Iev\n",
"B=(h*c)/L\n",
"B1=B/Iev\n",
"\n",
"#Result\n",
"print\"(i) The energy of a photon with frequency 1000 Khz is\",round(E1*10**3,2),\"10**-9\",\"ev\" \n",
"print\"(ii) The energy of a photon when wavelength is 5890A is\",round(A1,2) ,\"eV\"\n",
"print\"(iii) The energy of a photon when wavelength is 1 A is\", B1,\"eV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(i) The energy of a photon with frequency 1000 Khz is 4.14 10**-9 ev\n",
"(ii) The energy of a photon when wavelength is 5890A is 2.11 eV\n",
"(iii) The energy of a photon when wavelength is 1 A is 12412.5 eV\n"
]
}
],
"prompt_number": 38
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.4 Page no 801"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"l=0.66*10**-10 #m\n",
"h=6.62*10**-34 #Js\n",
"c=3*10**8 #m/s\n",
"\n",
"#Calculation\n",
"E=((h*c)/l)/(1.6*10**-19)\n",
"\n",
"#Result\n",
"print\"(a) Maximum energy of photon is\",round(E*10**-3,2),\"Kev\"\n",
"print\"(b) To produce electrons of energy 18.81 Kev,accelerating potential of 18.81 KV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a) Maximum energy of photon is 18.81 Kev\n",
"(b) To produce electrons of energy 18.81 Kev,accelerating potential of 18.81 KV\n"
]
}
],
"prompt_number": 45
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.5 Page no 801"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"E=10.2*10**9 #ev\n",
"h=6.62*10**-34\n",
"c=3*10**8\n",
"\n",
"#Calculation\n",
"E1=(E/2.0)*(1.6*10**-19)\n",
"l=(h*c)/E1\n",
"\n",
"#Result\n",
"print\"Wavelength is\",round(l*10**16,3),\"10**-16\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Wavelength is 2.434 10**-16\n"
]
}
],
"prompt_number": 60
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.6 Page no 802"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"L=3500.0*10**-10 #m\n",
"h=6.62*10**-34\n",
"c=3*10**8\n",
"\n",
"#Calculation\n",
"Hv=h*c/(L*(1.6*10**-19))\n",
"\n",
"#Result\n",
"print\"Energy of incident light is\", round(Hv,3),\"eV \\nMetal B will yield photoelectrons.\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Energy of incident light is 3.546 eV \n",
"Metal B will yield photoelectrons.\n"
]
}
],
"prompt_number": 75
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.7 Page no 802"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"l=6000.0*10**-10 #m\n",
"h=6.62*10**-34 #Js\n",
"e=1.6*10**-19\n",
"c=3*10**8\n",
"\n",
"#Calculation\n",
"v0=c/l\n",
"w=(h*v0)/e\n",
"\n",
"#Result\n",
"print\"(i) Threshold frequency is\", v0,\"Hz\"\n",
"print\"(ii) Work function is\",round(w,3),\"eV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(i) Threshold frequency is 5e+14 Hz\n",
"(ii) Work function is 2.069 eV\n"
]
}
],
"prompt_number": 83
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.8 Page no 802"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"w=1.2*1.6*10**-19\n",
"l=5000.0*10**-10\n",
"c=3*10**8\n",
"h=6.62*10**-34\n",
"e=1.6*10**-19\n",
"\n",
"#Calculation\n",
"A=((h*c)/l)-w\n",
"V0=A/e\n",
"\n",
"#Result\n",
"print\"Stopping potential is\", round(V0,2),\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Stopping potential is 1.28 V\n"
]
}
],
"prompt_number": 90
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.9 Page no 802"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"h=6.6*10**-34 #Js\n",
"e=1.6*10**-19\n",
"l=500.0*10**-9 #m\n",
"\n",
"#Calculation\n",
"w=2*e\n",
"l0=(h*c)/w\n",
"E=((h*c)/l)-w\n",
"v0=E/e\n",
"\n",
"#Result\n",
"print\"(i) The threshold wavelength is\", l0*10**9,\"nm\"\n",
"print\"(ii) Maximum energy is\",E*10**19,\"*10**-19 J\"\n",
"print\"(iii) The stopping potential is\",v0,\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(i) The threshold wavelength is 618.75 nm\n",
"(ii) Maximum energy is 0.76 *10**-19 J\n",
"(iii) The stopping potential is 0.475 V\n"
]
}
],
"prompt_number": 104
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.10 Page no 802"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"V0=1.3\n",
"l=2271*10**-10\n",
"h=6.62*10**-34\n",
"e=1.6*10**-19\n",
"c=3*10**8\n",
"\n",
"#Calculation\n",
"w=(h*c/l)-(V0*e)\n",
"l0=(h*c)/w\n",
"\n",
"#Result\n",
"print\"Work function of metal is\", round(l0*10**10,0),\"A\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Work function of metal is 2980.0 A\n"
]
}
],
"prompt_number": 109
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.11 Page no 803"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"h=6.62*10**-34\n",
"c=3*10**8\n",
"l=640.2*10**-9\n",
"e=1.6*10**-19\n",
"V0=0.54\n",
"l1=427.2*10**-9\n",
"\n",
"#Calculation\n",
"w=(h*c/l)-(e*V0)\n",
"v0=(((h*c)/l1)-w)/e\n",
"\n",
"#Result\n",
"print\"New stopping voltage is\", round(v0,3),\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"New stopping voltage is 1.507 V\n"
]
}
],
"prompt_number": 115
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.12 Page no 803"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"l=5600.0*10**-10 #m\n",
"h=6.625*10**-34\n",
"c=3*10**8\n",
"a=5\n",
"\n",
"#Calculation\n",
"E=h*c/l\n",
"n=a/E\n",
"\n",
"#Result\n",
"print\"Number of visible light photon is\", round(n*10**-19,2)*10**-19"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Number of visible light photon is 1.41e-19\n"
]
}
],
"prompt_number": 121
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.13 Page no 803"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"E=10**4 #W\n",
"l=500.0 #m\n",
"h=6.62*10**-34\n",
"A=0.4*10**-14 #m**2\n",
"i=10**-10 #W/m**2\n",
"v=6*10**14\n",
"\n",
"#Calculation\n",
"E1=E*l/(h*c)\n",
"E2=h*v\n",
"n=A/E2\n",
"\n",
"#Result\n",
"print\"(i) Number of photons emitted is\",round(E1*10**-31,3)*10**31\n",
"print\"(ii) Number of photons is\", round(n*10**-4,0),\"*10**4\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(i) Number of photons emitted is 2.518e+31\n",
"(ii) Number of photons is 1.0 *10**4\n"
]
}
],
"prompt_number": 132
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 28.14 Page no 803"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"A=2*10**-4 #m**2\n",
"An=10.0**-20\n",
"n1=5\n",
"i=10**-5 #W/m**2\n",
"\n",
"#Calculation\n",
"n=(A*n1)/An\n",
"E=i*A\n",
"E1=(E/n)/e\n",
"t=2/E1\n",
"\n",
"#Result\n",
"print\"Time required for the photoelectric emission is\",t*10**-7,\"*10**7 S\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Time required for the photoelectric emission is 1.6 *10**7 S\n"
]
}
],
"prompt_number": 145
}
],
"metadata": {}
}
]
}