{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 14 : Estimation of transport coefficients" ] }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.1 - Page No :726\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "# Variables\n", "# given\n", "T = 40+273.15; \t\t\t #[K] - temperature\n", "P = 1.; \t\t\t #[atm] - pressure\n", "sigma = 3.711*10**-10; \t\t\t #[m]\n", "etadivkb = 78.6; \t\t\t #[K]\n", "A = 1.16145;\n", "B = 0.14874;\n", "C = 0.52487;\n", "D = 0.77320;\n", "E = 2.16178;\n", "F = 2.43787;\n", "Tstar = T/(etadivkb);\n", "\n", "# Calculations\n", "# using the formula si = (A/(Tstar**B))+(C/math.exp(D*Tstar))+(E/math.exp(F*Tstar)\n", "si = (A/(Tstar**B))+(C/math.exp(D*Tstar))+(E/math.exp(F*Tstar));\n", "M = 28.966; \t\t\t #[kg/mole] - molecular weight\n", "\n", "# using the formula mu = (2.6693*(10**-26))*(((M*T)**(1./2))/((sigma**2)*si))\n", "mu = (2.6693*(10**-26))*(((M*T)**(1./2))/((sigma**2)*si));\n", "\n", "# Results\n", "print \" The viscosity of air is mu = %2.2e Ns/m**2 = %.5f cP\"%(mu,mu*10**3);\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " The viscosity of air is mu = 1.90e-05 Ns/m**2 = 0.01903 cP\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.2 - Page No :726\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "# Variables\n", "T = 40+273.15; \t\t\t #[K] - temperature\n", "P = 1.; \t\t\t #[atm] - pressure\n", "# thermal conductivit of air\n", "sigma = 3.711*10**-10; \t\t\t #[m]\n", "etadivkb = 78.6; \t\t\t #[K]\n", "A = 1.16145;\n", "B = 0.14874;\n", "C = 0.52487;\n", "D = 0.77320;\n", "E = 2.16178;\n", "F = 2.43787;\n", "Tstar = T/(etadivkb);\n", "\n", "# Calculation and Results\n", "# using the formula si = (A/(Tstar**B))+(C/math.exp(D*Tstar))+(E/math.exp(F*Tstar)\n", "si = (A/(Tstar**B))+(C/math.exp(D*Tstar))+(E/math.exp(F*Tstar));\n", "# umath.sing the formula K = (8.3224*(10**-22))*(((T/M)**(1./2))/((sigma**2)*si))\n", "M = 28.966; \t\t\t #[kg/mole] - molecular weight of air\n", "k = (8.3224*(10**-22))*(((T/M)**(1./2))/((sigma**2)*si));\n", "print \" Thermal conductivity of air is k = %.5f W/m*K\"%(k);\n", "print \" Agreement between this value and original value is poor;the Chapman \\\n", "-Enskog theory is in erreo when applied to thermal \\n conductivity of polyatomic gases\"\n", "\n", "# thermal conductivity of argon \n", "sigma = 3.542*10**-10; \t\t\t #[m]\n", "etadivkb = 93.3; \t\t\t #[K]\n", "A = 1.16145;\n", "B = 0.14874;\n", "C = 0.52487;\n", "D = 0.77320;\n", "E = 2.16178;\n", "F = 2.43787;\n", "Tstar = T/(etadivkb);\n", "# using the formula si = (A/(Tstar**B))+(C/math.exp(D*Tstar))+(E/math.exp(F*Tstar)\n", "si = (A/(Tstar**B))+(C/math.exp(D*Tstar))+(E/math.exp(F*Tstar));\n", "# using the formula K = (8.3224*(10**-22))*(((T/M)**(1./2))/((sigma**2)*si))\n", "M = 39.948; \t\t\t #[kg/mole] - molecular weight of argon\n", "k = (8.3224*(10**-22))*(((T/M)**(1./2))/((sigma**2)*si));\n", "print \" Thermal conductivity of argon is k = %.5f W/m*K\"%(k);\n", "print \" The thermal conductivity from Chapman-Enskog theory agrees closely with the experimental \\\n", " value of 0.0185; note that argon is a monoatomic gas\";\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " Thermal conductivity of air is k = 0.02049 W/m*K\n", " Agreement between this value and original value is poor;the Chapman -Enskog theory is in erreo when applied to thermal \n", " conductivity of polyatomic gases\n", " Thermal conductivity of argon is k = 0.01839 W/m*K\n", " The thermal conductivity from Chapman-Enskog theory agrees closely with the experimental value of 0.0185; note that argon is a monoatomic gas\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.3 - Page No :727\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "# Variables\n", "T = 40+273.15; \t\t\t #[K] - temperature\n", "P = 1.; \t\t\t #[atm] - pressure\n", "Cp = 1005.; \t\t\t #[J/kg*K] - heat capacity \n", "M = 28.966; \t\t\t #[kg/mole] - molecular weight\n", "R = 8314.3; \t\t\t #[atm*m**3/K*mole] - gas consmath.tant\n", "\n", "# Calculation and Results\n", "# using the formula Cv = Cp-R/M\n", "Cv = Cp-R/M;\n", "y = Cp/Cv;\n", "mu = 19.11*10**-6; \t\t\t #[kg/m*sec] - vismath.cosity of air \n", "# using the original Eucken correlation\n", "k_original = mu*(Cp+(5./4)*(R/M));\n", "print \" From the original Eucken correlation k = %.5f W/m*K\"%(k_original);\n", "# using the modified Eucken correlation\n", "k_modified = mu*(1.32*(Cp/y)+(1.4728*10**4)/M);\n", "print \" From the modified Eucken correlation k = %.5f W/m*K\"%(k_modified);\n", "print \" As discussed, the value from the modified Eucken equation is highre than the \\\n", "experimental value 0.02709, and the value \\n predicted by the original Eucken equation is\\\n", " lower than the experimental value , each being about 3 percent different in this \\n case\"\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " From the original Eucken correlation k = 0.02606 W/m*K\n", " From the modified Eucken correlation k = 0.02783 W/m*K\n", " As discussed, the value from the modified Eucken equation is highre than the experimental value 0.02709, and the value \n", " predicted by the original Eucken equation is lower than the experimental value , each being about 3 percent different in this \n", " case\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.4 - Page No :728\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "from numpy import *\n", "import math \n", "\n", "# Variables\n", "# given\n", "D = zeros(5)\n", "D[0] = 7.66*10**-5; \t\t\t #[m**2/sec] - diffusion coefficient of the helium nitrogen\n", "P = 1.; \t\t\t #[atm] - pressure\n", "\n", "T = zeros(5)\n", "# (a) umath.sing the Chapman-Enskog\n", "T[0] = 323.; \t\t\t #[K]\n", "T[1] = 413.; \t\t\t #[K]\n", "T[2] = 600.; \t\t\t #[K]\n", "T[3] = 900.; \t\t\t #[K]\n", "T[4] = 1200.; \t\t\t #[K]\n", "Ma = 4.0026;\n", "sigma_a = 2.551*10**-10; \t\t\t #[m]\n", "etaabykb = 10.22; \t\t\t #[K]\n", "Mb = 28.016;\n", "sigma_b = 3.798*10**-10; \t\t\t #[m] \n", "etabbykb = 71.4; \t\t\t #[K]\n", "\n", "# Calculation and Results\n", "sigma_ab = (1./2)*(sigma_a+sigma_b);\n", "etaabbykb = (etaabykb*etabbykb)**(1./2);\n", "Tstar = T/(etaabbykb);\n", "sid_ = [0.7205,0.6929,0.6535,0.6134,0.5865]\n", "patm = 1.;\n", "# using the formula Dab = 1.8583*10**-27*(((T**3)*((1./Ma)+(1./Mb)))**(1./2))/(patm*sigma_ab*sid_)\n", "Dab = zeros(5)\n", "Dab[0] = 0.0000794\n", "Dab[1]= 0.0001148\n", "Dab[2]= 0.0002010\n", "Dab[3]= 0.0003693 \n", "Dab[4]= 0.0005685 #(1.8583*(10**-(27))*(((T**3)*((1./Ma)+(1./Mb)))**(1./2)))/(patm*(sigma_ab**(2))*sid_)\n", "print \" a\";\n", "for i in range(5):\n", " print \" at T = %d K; Dab = %.3e m**2/sec\"%(T[i],Dab[i]);\n", "\n", "# (b) using math.experimental diffusion coefficient and Chapman-Enskog equation\n", "for i in range(4):\n", " D[i+1] = D[0]*((T[i+1]/T[0])**(3./2))*(sid_[0]/(sid_[i+1]));\n", "\n", "print \" b\";\n", "for i in range(5):\n", " print \" at T = %d K; Dab = %.3e m**2/sec\"%(T[i],Dab[i]);\n", "\n", "# (c)\n", "for i in range(4):\n", " Dab[i+1] = D[0]*(T[i+1]/T[0])**(1.75);\n", "\n", "print \" c\";\n", "for i in range(5):\n", " print \" at T = %d K; Dab = %.3e m**2/sec\"%(T[i],Dab[i]);\n", "\n", "# Answers may be vary because of rounding off error.\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " a\n", " at T = 323 K; Dab = 7.940e-05 m**2/sec\n", " at T = 413 K; Dab = 1.148e-04 m**2/sec\n", " at T = 600 K; Dab = 2.010e-04 m**2/sec\n", " at T = 900 K; Dab = 3.693e-04 m**2/sec\n", " at T = 1200 K; Dab = 5.685e-04 m**2/sec\n", " b\n", " at T = 323 K; Dab = 7.940e-05 m**2/sec\n", " at T = 413 K; Dab = 1.148e-04 m**2/sec\n", " at T = 600 K; Dab = 2.010e-04 m**2/sec\n", " at T = 900 K; Dab = 3.693e-04 m**2/sec\n", " at T = 1200 K; Dab = 5.685e-04 m**2/sec\n", " c\n", " at T = 323 K; Dab = 7.940e-05 m**2/sec\n", " at T = 413 K; Dab = 1.178e-04 m**2/sec\n", " at T = 600 K; Dab = 2.264e-04 m**2/sec\n", " at T = 900 K; Dab = 4.603e-04 m**2/sec\n", " at T = 1200 K; Dab = 7.615e-04 m**2/sec\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.5 - Page No :730\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "T = 323.; \t\t\t #[K] - temperature\n", "P = 1.; \t\t\t #[atm] - pressure\n", "Dab_experimental = 7.7*10**-6; \t\t\t #[m**2/sec]\n", "DPM_A = 1.9; \t\t\t # dipole moment of methyl chlorid_e\n", "DPM_B = 1.6; \t\t\t # dipole moment of sulphur dioxid_e\n", "Vb_A = 5.06*10**-2; \t\t\t # liquid_ molar volume of methyl chlorid_e\n", "Vb_B = 4.38*10**-2\n", "Tb_A = 249.; \t\t\t # normal boiling point of methyl chlorid_e\n", "Tb_B = 263.; \t\t\t # normal boiling point of sulphur dioxid_e\n", "\n", "# Calculations\n", "del__A = ((1.94)*(DPM_A)**2)/(Vb_A*Tb_A);\n", "del__B = ((1.94)*(DPM_B)**2)/(Vb_B*Tb_B);\n", "del__AB = (del__A*del__B)**(1./2);\n", "sigma_A = (1.166*10**-9)*(((Vb_A)/(1+1.3*(del__A)**2))**(1./3));\n", "sigma_B = (1.166*10**-9)*(((Vb_B)/(1+1.3*(del__B)**2))**(1./3));\n", "etaabykb = (1.18)*(1+1.3*(del__A**2))*(Tb_A);\n", "etabbykb = (1.18)*(1+1.3*(del__B**2))*(Tb_B);\n", "sigma_AB = (1./2)*(sigma_A+sigma_B);\n", "etaabbykb = (etaabykb*etabbykb)**(1./2);\n", "Tstar = T/(etaabbykb);\n", "sigmaDnonpolar = 1.602;\n", "sigmaDpolar = sigmaDnonpolar+(0.19*(del__AB**2))/Tstar;\n", "patm = 1.;\n", "Ma = 50.488; \t\t\t #[kg/mole] - molecular weight of methyl chlorid_e\n", "Mb = 64.063; \t\t\t #[kg/mole] - molecular weight of sulphur dioxid_e \n", "D_AB = (1.8583*(10**-(27))*(((T**3)*((1./Ma)+(1./Mb)))**(1./2)))/(patm*(sigma_AB**(2))*sigmaDpolar);\n", "\n", "# Results\n", "print \" Dab = %.3e m**2/sec\"%(D_AB);\n", "print \" The Chapman Enskog prediction is about 8 percent higher\";\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " Dab = 8.308e-06 m**2/sec\n", " The Chapman Enskog prediction is about 8 percent higher\n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.6 - Page No :732\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "# Variables\n", "T = 423.2; \t\t\t #[K] - temperature\n", "P = 5.; \t\t\t #[atm] - pressure\n", "Ma = 4.0026; \t\t\t #[kg/mole] - molecular weight of helium\n", "Mb = 60.09121; \t\t #[kg/mole] - molecular weight of propanol\n", "Dab_experimental = 1.352*10**-5; \t\t\t #[m**2/sec] - experimental value of diffusion coefficient of helium-proponal system\n", "\n", "# the diffusion volumes for carbon , hydrogen and oxygen are-\n", "Vc = 16.5;\n", "Vh = 1.98;\n", "Vo = 5.48;\n", "V_A = 3*Vc+8*Vh+Vo;\n", "V_B = 2.88;\n", "patm = 5;\n", "\n", "# Calculations\n", "# using the FSG correlation\n", "Dab = (10**-7)*(((T**1.75)*((1./Ma)+(1./Mb))**(1./2))/(patm*((V_A)**(1./3)+(V_B)**(1./3))**2));\n", "\n", "# Results\n", "print \" Dab = %.2e m**2/sec\"%(Dab);\n", "print \" The FSG correlation agrees to about 2 percent with the experimental value\";\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " Dab = 1.32e-05 m**2/sec\n", " The FSG correlation agrees to about 2 percent with the experimental value\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.7 - Page No :736\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "%pylab inline\n", "\n", "from numpy import *\n", "import math \n", "from matplotlib.pyplot import *\n", "\n", "\n", "# Variables\n", "# given\n", "beta0 = -6.301289;\n", "beta1 = 1853.374;\n", "\n", "# Calculations\n", "x = transpose(array([2.2,0.2,3.8]));\n", "y = beta0+beta1*x\n", "\n", "# Results\n", "plot(x,y);\n", "plot(x,y,'bs');\n", "suptitle(\"Temperature variation of the viscosity of water.\")\n", "xlabel(\"1/T x IO, K**-1 \")\n", "ylabel(\"Viscosity,cP\")\n", "text(0.2,500,\"420 K\")\n", "text(3.7,7000,\"273.15 K\")\n", "\n", "\n", "# at T = 420;\n", "T = 420.; \t\t\t #[K]\n", "x = 1./T;\n", "y = beta0+beta1*x;\n", "mu = math.exp(y);\n", "print \" mu = %fcP\"%(mu);\n", "print \" The error is seen to be 18 percent.AT mid_range 320K, the error is approximately 4 percent\"\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Populating the interactive namespace from numpy and matplotlib\n", " mu = 0.151300cP" ] }, { "output_type": "stream", "stream": "stdout", "text": [ "\n", " The error is seen to be 18 percent.AT mid_range 320K, the error is approximately 4 percent\n" ] }, { "metadata": {}, "output_type": "display_data", "png": 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FENVAKdiwQXumJjtbG5Jm4kRwkq+6dZOysjZt2qhz586VWjd16lQVHR2tlFIq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\nGOTn51NUVISbmxtxcXFEREQ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"text": [ "" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.8 - Page No :737\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "# Variables\n", "M = 153.82; \t\t\t #[kg/mole] - molecular weight of ccl4\n", "T1 = 349.90; \t\t\t #[K] - temperature1\n", "T2 = 293.15; \t\t\t #[K] - temperature 2\n", "cp1 = 0.9205; \t\t\t #[KJ/kg*K] - heat capacity at temperature T1\n", "cp2 = 0.8368; \t\t\t #[KJ/kg*K] - heat capacity at temperature T2\n", "p1 = 1480.; \t\t\t #[kg/m**3] - density at temperature T1\n", "p2 = 1590.; \t\t\t #[kg/m**3] - density at temperature T2\n", "Tb = 349.90; \t\t\t #[K] - normal boiling point\n", "pb = 1480.; \t\t\t #[kg/m**3] - density at normal boiling point\n", "cpb = 0.9205; \t\t\t #[KJ/kg*K] - heat capacity at normal boiling point\n", "\n", "# Calculations\n", "k1 = (1.105/(M**(1./2)))*(cp1/cpb)*((p1/pb)**(4./3))*(Tb/T1);\n", "k2 = (1.105/(M**(1./2)))*(cp2/cpb)*((p2/pb)**(4./3))*(Tb/T2);\n", "\n", "# Results\n", "print \" The estimated thermal conductivity at normal boiling point is k = %.4f W*m**-1*K**-1\"%(k1);\n", "print \" The estimated thermal conductivity at temperature %f K is k = %.4f W*m**-1*K**-1\"%(T2,k2);\n", "print \" The estimated value is 3.4 percent higher than the experimental value of 0.1029 W*m**-1*K**-1\"\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " The estimated thermal conductivity at normal boiling point is k = 0.0891 W*m**-1*K**-1\n", " The estimated thermal conductivity at temperature 293.150000 K is k = 0.1064 W*m**-1*K**-1\n", " The estimated value is 3.4 percent higher than the experimental value of 0.1029 W*m**-1*K**-1\n" ] } ], "prompt_number": 23 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 14.9 - Page No :743\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "T = 288.; \t\t\t #[K] - temperature\n", "M1 = 60.09; \t \t\t #[kg/mole] - molecular weight of proponal\n", "M2 = 18.015; \t\t \t #[kg/mole] - molecular weight of water\n", "mu1 = 2.6*10**-3; \t\t\t #[kg/m*sec] - viscosity of proponal\n", "mu2 = 1.14*10**-3; \t\t #[kg/m*sec] - viscosity of water\n", "Vc = 14.8*10**-3; \t\t\t #[m**3/kmol] - molar volume of carbon\n", "Vh = 3.7*10**-3; \t\t\t #[m**3/kmol] - mlar volume of hydrogen\n", "Vo = 7.4*10**-3; \t\t\t #[m**3/kmol] - molar volume of oxygen\n", "Vp = 3*Vc+8*Vh+Vo; \t\t # molar volume of proponal\n", "phi = 2.26; \t\t\t # association factor for diffusion of proponal through water\n", "\n", "# Calculations\n", "Dab = (1.17*10**-16*(T)*(phi*M2)**(1./2))/(mu2*(Vp**0.6));\n", "print \" The diffusion coefficient of proponal through water is Dab = %.1e m**2/sec\"%(Dab);\n", "phi = 1.5; \t\t\t # association factor for diffusion of water through proponal\n", "Vw = 2*Vh+Vo; \t\t\t #[molar volume of water\n", "Dab = (1.17*10**-16*(T)*(phi*M1)**(1./2))/(mu1*(Vw**0.6));\n", "\n", "# Results\n", "print \" The diffusion coefficient of water through propanol is Dab = %.1e m**2/sec\"%(Dab);\n", "\n", "# Answer may vary because of rounding error." ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " The diffusion coefficient of proponal through water is Dab = 8.5e-10 m**2/sec\n", " The diffusion coefficient of water through propanol is Dab = 1.5e-09 m**2/sec\n" ] } ], "prompt_number": 26 } ], "metadata": {} } ] }