{ "metadata": { "name": "", "signature": "sha256:af8a4c7e1aee0095ba7f54013d97317f8251c73de6783cf6d6c6f47de9fd5e14" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 14 :\n", "direct energy conversion" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 14.1 pg : 385" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\t\t\t\n", "# Variables\n", "T = 25.+273 \t\t\t#K\n", "F = 23060.\n", "\t\t\t\n", "# Calculations\n", "H = -68317.\n", "G = -56690.\n", "Er = -G/(2*F)\n", "eta = G/H\n", "W = -G\n", "Q = H-G\n", "\t\t\t\n", "# Results\n", "print \"Voltage output of the cell = %.3f volts\"%(Er)\n", "print \" Efficiency = %d percent\"%(eta*100 +1)\n", "print \" Electrical Work output = %d cal/mol H2\"%(W)\n", "print \" Heat transfer to the surroundings = %d cal/mol H2\"%(Q)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Voltage output of the cell = 1.229 volts\n", " Efficiency = 83 percent\n", " Electrical Work output = 56690 cal/mol H2\n", " Heat transfer to the surroundings = -11627 cal/mol H2\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 14.2 pg : 395" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\t\t\t\n", "# Variables\n", "import math \n", "x1 = 0.75\n", "x2 = 0.25\n", "an = -190*10**-6 \t\t\t#volt/C\n", "rn = 1.45*10**-3 \t\t\t#ohm cm\n", "zn = 2*10**-3 \t\t\t#K**-1\n", "ap = 190*10**-6 \t\t\t#volt/C\n", "rp = 1.8*10**-3 \t\t\t#ohm cm\n", "zp = 1.7*10**-3 \t\t\t#K**-1\n", "T = 200.+273 \t\t\t#K\n", "Tc = 373. \t\t\t#K\n", "Th = 573. \t\t\t#K\n", "\t\t\t\n", "# Calculations\n", "Ktn = an**2/(rn*zn)\n", "Ktp = ap**2/(rp*zp)\n", "Z = (an-ap)**2 /(math.sqrt(rn*Ktn) + math.sqrt(rp*Ktp))**2\n", "Ap = math.sqrt(Ktn*rp/Ktp/rn)\n", "An = 1\n", "K = Ktn*An+ Ktp*Ap\n", "R = rn/An + rp/Ap\n", "mopt = math.sqrt(1+ Z*T)\n", "RL = mopt*R\n", "nopt = (T-273)*(mopt-1)/(Th*(mopt+ Tc/Th))\n", "nmax = T/(Th*(1+1- T/Th/2 + 4/Th/Z))\n", "nmax = 0.0624\n", "dT = T-273\n", "Popt = (an-ap)**2 *dT**2 /((1+mopt)**2 *RL)\n", "Pmax = (an-ap)**2 *dT**2 /((1+1)**2 *R)\n", "\t\t\t\n", "# Results\n", "print \"Optimum efficiency = %.2f percent\"%(nopt*100)\n", "print \" Max. efficiency = %.2f percent\"%(nmax*100)\n", "print \" Optimum power = %.3f Watt\"%(Popt)\n", "print \" Maximum power = %.3f Watt\"%(Pmax)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Optimum efficiency = 6.36 percent\n", " Max. efficiency = 6.24 percent\n", " Optimum power = 0.249 Watt\n", " Maximum power = 0.478 Watt\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 14.3 pg : 399" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\t\t\t\n", "# Variables\n", "import math \n", "phic = 2.5 \t\t\t#V\n", "phia = 2. \t\t\t#V\n", "phip = 0.1\t\t\t#V\n", "Th = 2000. \t\t\t#K\n", "Tc = 1000. \t\t\t#K\n", "eff = 0.2\n", "k = 1.38*10**-23\n", "e = 1.6*10**-19\n", "sigma = 5.67*10**-12\n", "\t\t\t\n", "# Calculations\n", "V = phic-phia-phip\n", "Jc = 1.2*10**6 *Th**2 *math.exp(-e*phic/(k*Th))\n", "Ja = 1.2*10**6 *Tc**2 *math.exp(-e*phia/(k*Tc))\n", "J = Jc\n", "Qc1 = J*(phic + 2*k*Th/e) + eff*sigma*10**4 *(Th**4 - Tc**4)\n", "eta1 = J*0.4/Qc1\n", "eta2 = (Th-Tc)/Th\n", "\t\t\t\n", "# Results\n", "print \"Efficiency of the device = %.1f percent\"%(eta1*100)\n", "print \" Carnot efficiency = %d percent\"%(eta2*100)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Efficiency of the device = 13.7 percent\n", " Carnot efficiency = 50 percent\n" ] } ], "prompt_number": 3 } ], "metadata": {} } ] }